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Musya8 [376]
2 years ago
6

Wayne needs to drive 470 miles to reach Milwaukee. Suppose he drives at a constant speed of 50 miles per hour. Which function re

presents Wayne’s distance in miles from Milwaukee in terms of the number of hours he drives?
A.
y = 420x
B.
y = 470 + 50x
C.
y = 50 − 470x
D.
y = 50 + 470x
E.
y = 470 − 50x
Mathematics
1 answer:
Gelneren [198K]2 years ago
7 0

Let the number of hours driven equal x.

You would multiply the number of hours by his speed, so you would have 50x

You would then want to subtract that from the total miles to see how many more miles he needs to drive.

The answer would be E. y = 470 - 50x

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Chandra's Average Monthly Expenses are;

1) For Both Jan and Feb are $269

2) For the remaining 10 months each are $244

Step-by-step explanation:

From Chandra's matrix all monthly expenses are all same that is,

Cell phone $71, Rent $1,025, Gym $75, Internet $25, Auto insurance $425, Gas $ 120, Food $145. which are all the expenses carried out every month for 12 months.

That means Chandra carries out a total of 7 expenses for the month of January and February while she carried a total of 6 expenses for the remaining 10 month which was noted from the matrix that Auto insurance was carried out only in the month of January and February.

Therefore, you start by adding up each month total expenses, which are ;

January = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

February = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

March = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

April = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

May = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

June = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

July= $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

August = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

September = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

October = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

November = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

December = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

Therefore Chandra's Average Monthly Expenses are:

1) January & February  = \frac{71 + 1,025 + 75 + 25 + 425 + 120 + 145}{7} = \frac{1886}{7} = 269.4286 to the nearest cent

≅ $269

2) For the remaining 10 month are = \frac{71 + 1,025 + 75 + 25  + 120 + 145}{6} = \frac{1461}{6}= 243.5 to the nearest cent

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<em><u>Question:</u></em>

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<em><u>The simple interest is given by formula:</u></em>

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