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hram777 [196]
2 years ago
12

At the end of a snow storm, Amelia saw there was a lot of snow on her front lawn. The temperature increased and the snow began t

o melt at a steady rate. After the storm, the snow started melting at a rate of 1.5 inches per hour and it is known that 4 hours after the storm ended, the depth of snow was down to 12 inches. Write an equation for S, in terms of t, representing the depth of snow on Amelia's lawn, in inches, t hours after the snow stopped falling.
Mathematics
1 answer:
Andrei [34K]2 years ago
5 0

Answer:

The equation is;

S = 18 - 1.5t  

Step-by-step explanation:

From the question, we are made to know that the depth of the snow is S and the time taken to melt in hours is t

After 4 hours of melting, the snow depth is 12 inches  

Now, recall that the rate of melting is 1.5 inches/ hour  

So in the 4 hours, the amount of snow melted will be 1.5 * 4 = 6 inches  

So the total depth of the snow initially will be 6 + 12 = 18 inches  

So let’s write the equation;

S = 18 - 1.5t  

Where S is the depth of the snow after a particular number of hours t

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How many intersections are there of the graphs of the equations below?
kipiarov [429]

Answer:

<u>The number of intersections = ∞</u>

Step-by-step explanation:

Given the system of equations:

0.5 x + 5y = 6

3x + 30y = 36

By multiplying the first equation by 6

∴ 6 (0.5 x + 5y) = 6 * 6

∴ 3x + 30y = 36

So, Those equations are "Dependent", because they are really the same equation, just multiplied the first equation by 6.

So, the two equations are identical

Therefore: <u>They have infinity number of solutions.</u>

<u>See the attached figure.</u>

0.5 x + 5y = 6 ⇒ in black color

3x + 30y = 36 ⇒ in red color

6 0
2 years ago
A sociologist wishes to estimate the average number of automobile thefts in a large city per day within 2 automobiles. He wishes
anzhelika [568]

Answer:

n=(\frac{2.58(4.2)}{2})^2 =29.35 \approx 30

So the answer for this case would be n=30 rounded up to the nearest integer

Step-by-step explanation:

Information given

ME = 2 the margin of error desired

\sigma =4.2 standard deviation from previous studies

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =2 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 99% of confidence interval now can be founded using the normal distribution. The significance level is \alpha=0.01 and the critical value would be z_{\alpha/2}=2.58, replacing into formula (b) we got:

n=(\frac{2.58(4.2)}{2})^2 =29.35 \approx 30

So the answer for this case would be n=30 rounded up to the nearest integer

5 0
2 years ago
Two of the steps in the derivation of the quadratic formula are shown below. Step 6: StartFraction b squared minus 4 a c Over 4
sergeinik [125]

Answer:

Step-by-step explanation:

From the step given step 6

(b² — 4ac) / 4a² = (x + b/2a)²

Mistake in question it is (x + b/2a)²

Step 7 given

±√(b² —4ac) /2a = x + b/2a

Mistake in question it is over 2a and not 1a.

1. The step taken from step 6 to step 7 is taking square roots of both sides

(b² — 4ac) / 4a² = (x + b/2a)²

Taking square of both sodes

√(b²—4ac) / √4a² = √(x + b/2a)²

√(b²—4ac) / 2a = x + b/2a

This is the required step 7.

Now, subtracting b/2a from both sides

√(b²—4ac) / 2a - b/2a= x + b/2a -b/2a

√(b²—4ac) / 2a — b/2a = x

(√(b²—4ac)  — b)/2a = x

x = [—b ± √(b²—4ac)] / 2a

So, this is the required formula method

The discriminant is D = b²—4ac.

6 0
2 years ago
Read 2 more answers
Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (
kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2}) is given as continuous function, so there exist lim_{(x,y)\rightarrow(0,0)}f(x,y) and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})

we know that cos^2A+sin^2A=1, so we have that

f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)

lim_{(x,y)\rightarrow(0,0)}f(x,y)=lim_{r\rightarrow0}f(r,A)=ln19

So f(0,0)=ln19.

8 0
2 years ago
Can someone help me solve this :
bija089 [108]

Answer:

The total cost of 5 pillows and 7 sheets is $205.345

Step-by-step explanation:

Let x be the price of pillow case

We are given that the price of the pillows is 3 times as much as the price of a pillow case

Price of pillow = 3x

Price of 2 pillows = 2(3x)=6x

Price of 3 pillow case = 3x

At a store, 2 pillows and 3 pillow cases together cost $73.08.

So, 6x+3x=73.08

9x=73.08

x=\frac{73.08}{9}

x=8.12

So, Price of 1 pillow case = 8.12

Price of 1 pillow = 3x=3(8.12)=24.36

Price of 3 pillow =3(24.36)=73.08

Let y be the cost of 1 sheet

The total cost of 3 pillows and 4 sheets is $120.82

So, 73.08+4y=120.82

y=\frac{120.82-73.08}{4}

y=11.935

Price of 1 sheet = 11.935

Price of 7 sheets = 7(11.935)=83.545

Price of 5 pillows =5(24.36)=121.8

So,the total cost of 5 pillows and 7 sheets=83.545+121.8=205.345

Hence the total cost of 5 pillows and 7 sheets is $205.345

5 0
2 years ago
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