Answer:
He needs 5x+56 ft
Step-by-step explanation:
To find how much of fencing he needs , we find the perimeter of the given figure
All sides are equal in a square
To find perimeter of the square we add all the sides
4 sides we have for the square
one side is x, so perimeter of square = x+x+x+x= 4x
Now we find perimeter of rectangle
Opposite sides of rectangle are equal
Here for rectangle we consider only three sides
because fourth side is common for rectangle and square
So perimeter of the rectangle (with 3 sides) = 28 +x+ 28 = 56+x
Total fencing = perimeter of square + perimeter of rectangle
4x + 56 + x= 5x+56
Answer:
The lateral area is equal to
Step-by-step explanation:
In this problem the lateral area is equal to the area of one equilateral triangle multiplied by 
To find the area of one equilateral triangle calculate the height
The area of the triangle is equal to
we have
Applying the Pythagoras theorem
The area of one triangle is equal to
so
The lateral area is equal to
1 feet is 12 inches so 40 feets is 480 inches
Real locomotive is 480/16=30 times wider then the model
And then a window on the real locomotive is 30 times wider then the model.
Answer:
125π√3/3 cm³ ≈ 226.72 cm³
Step-by-step explanation:
The length of the circular edge of the half-circle is ...
(1/2)C = (1/2)(2πr) = πr = 10π . . . . cm
This is the circumference of the circular edge of the cone, so the radius of the cone is found from ...
C = 2πr
10π = 2πr . . . . fill in the numbers; next, solve for r
r = 5 . . . . cm
The slant height of the cone is the original radius, 10 cm, so the height of the cone from base to apex is found from the Pythagorean theorem.
(10 cm)² = h² + r²
h = √((10 cm)² -(5 cm)²) = 5√3 cm
And the cone's volume is ...
V = 1/3·πr²h = (1/3)π(5 cm)²(5√3 cm)
V = 125π√3/3 cm³ ≈ 226.72 cm³
Answer:
Number of rectangles could alex draw with an area of 11cm² = 1
Step-by-step explanation:
Minimum length in centimeter grid = 1 cm
Alex is drawing rectangles with different areas on a centimetre grid.He can draw 3 different rectangles with an area of 12cm²
That is
These are the 3 different rectangles with an area of 12cm².
Now we need to find how many rectangles could alex draw with an area of 11cm².
11 = 1 x 11
So only one factorization is possible.
Number of rectangles could alex draw with an area of 11cm² = 1
