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2 years ago

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Lacey is attending a university where the cost for one year is $10,500. She has a scholarship worth $6,000 and a grant worth $90

0. She earns $45 a day at her job. How many days does she need to work to pay for 50% of the remaining amount?

1 answer:

Alexus [3.1K]2 years ago

7 0

She needs to work 40 days. $10,500 - $6,900 = $3,600. Half of this is $1800, so then we set up an equation. If d represents days, the 45d = $1800. Divide each side by 45 to isolate the variable. $1800 divided by 45 gives us 40 days (d = 40).

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So 72 pencils and 24 calculators
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this means
what is the biggest number that we can divide 72 and 24 by and get a whole number
this is called the GCM or greatest common multipule

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72 divided by 24=72/24=3
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2 years ago

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the ratio of the measures of the sides of a triangle is 21:8:14 if the perimeter of the triangle is 215 feet find the length of

SOVA2 [1]

Answer:

the 3 sides of the triangle are 105 ft, 40 ft and 70 ft.

Step-by-step explanation:

the perimeter is the sum of the 3 sides of the triangle

add the parts of the ratio 21 + 8 + 14 = 43

divide the perimeter by 43 to find the value of one part of the ratio

= 5 ft ← 1 part of the ratio, hence

21 parts = 21 × 5 = 105 ft

8 parts = 8 × 5 = 40 ft

14 parts = 14 × 5 = 70 ft

the 3 sides of the triangle are 105 ft, 40 ft and 70 ft

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A ramp with a constant incline is made to connect a driveway to a front door. At a point 4 feet from the driveway, the height of

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So, we're finding ratios first okay, for every 4ft:12in and 6ft:18in so for every one foot there is 3 inches which is your rate of incline 1:3 or every one foot there are 3 inches of incline hope this helped you have an amazing day

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Darnell is constructing a rectangle window frame. He measured the length, the width, and the diagonal as 26 inches, 32 inches, a

OleMash [197]

Answer:

What is the longest side?

square root of 1700

What is the square of the longest side?

1700

What is the sum of the squares of the two shorter sides?

1700

Does the window frame form right triangles?

Yes, the sum of the square of the two shorter sides equals the square of the longest side.

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2 years ago

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During April of 2013, Gallup randomly surveyed 500 adults in the US, and 47% said that they were happy, and without a lot of str

Brilliant_brown [7]

Answer:

number of successes

$k = 235$

number of failure

$y = 265$

The criteria are met

A

The sample proportion is $\r p = 0.47$

B

$E =4.4 \%$

C

What this mean is that for N number of times the survey is carried out that the which sample proportion obtain will differ from the true population proportion will not more than 4.4%

Ci

$r = 0.514 = 51.4 \%$

$v = 0.426 = 42.6 \%$

D

This 95% confidence interval mean that the the chance of the true population proportion of those that are happy to be exist within the upper and the lower limit is 95%

E

Given that 50% of the population proportion lie with the 95% confidence interval the it correct to say that it is reasonably likely that a majority of U.S. adults were happy at that time

F

Yes our result would support the claim because

$\frac{1}{3 } \ of N < \frac{1}{2} (50\%) \ of \ N , \ Where\ N \ is \ the \ population\ size$

Step-by-step explanation:

From the question we are told that

The sample size is $n = 500$

The sample proportion is $\r p = 0.47$

Generally the number of successes is mathematical represented as

$k = n * \r p$

substituting values

$k = 500 * 0.47$

$k = 235$

Generally the number of failure is mathematical represented as

$y = n * (1 -\r p )$

substituting values

$y = 500 * (1 - 0.47 )$

$y = 265$

for approximate normality for a confidence interval criteria to be satisfied

$np > 5 \ and \ n(1- p ) \ >5$

Given that the above is true for this survey then we can say that the criteria are met

Given that the confidence level is 95% then the level of confidence is mathematically evaluated as

$\alpha = 100 - 95$

$\alpha = 5 \%$

$\alpha =0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table, the value is

$Z_{\frac{ \alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{ \frac{\r p (1- \r p}{n} }$

substituting values

$E = 1.96 * \sqrt{ \frac{0.47 (1- 0.47}{500} }$

$E = 0.044$

=> $E =4.4 \%$

What this mean is that for N number of times the survey is carried out that the proportion obtain will differ from the true population proportion of those that are happy by more than 4.4%

The 95% confidence interval is mathematically represented as

$\r p - E < p < \r p + E$

substituting values

$0.47 - 0.044 < p < 0.47 + 0.044$

$0.426 < p < 0.514$

The upper limit of the 95% confidence interval is $r = 0.514 = 51.4 \%$

The lower limit of the 95% confidence interval is $v = 0.426 = 42.6 \%$

This 95% confidence interval mean that the the chance of the true population proportion of those that are happy to be exist within the upper and the lower limit is 95%

Given that 50% of the population proportion lie with the 95% confidence interval the it correct to say that it is reasonably likely that a majority of U.S. adults were happy at that time

Yes our result would support the claim because

$\frac{1}{3 } < \frac{1}{2} (50\%)$

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2 years ago