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RUDIKE [14]
2 years ago
14

Lennox was curious if triangles \triangle ABE△ABEtriangle, A, B, E and \triangle DCE△DCEtriangle, D, C, E were similar, so she t

ried to map one figure onto the other using a reflection and a dilation. Lennox concluded: "It's not possible to map \triangle DCE△DCEtriangle, D, C, E onto \triangle ABE△ABEtriangle, A, B, E using a sequence of rigid transformations and dilations, so the triangles are not similar." What error did Lennox make in her conclusion?

Mathematics
2 answers:
just olya [345]2 years ago
7 0

Answer:

<u>There is no error. This is a correct conclusion.</u>

Step-by-step explanation:

If a sequence of rigid transformations

(translations, reflections, and rotations) and dilations can map △DCE onto △ABE, then the figures are similar.

Notice that both triangles are right triangles (at vertices B and C), with line AB and DC being the longer legs.

Therefore, if the triangles are similar, we should be able to map each pair of corresponding points onto each other with rigid transformations and dilations:

   D should be mapped onto A.

   C should be mapped onto B.

   E should be mapped onto itself.

Lennox used a reflection across line BE and a dilation about E to get △DCE as close as possible to △ABE. But still, point D did not map onto point A.

So we can conclude that it's not possible to map △DCE onto △ABE using a sequence of rigid transformations and dilations.

Lennox concluded:

"It's not possible to map △DCE onto △ABE using a sequence of rigid transformations and dilations, so the triangles are not similar."

<u>There is no error. This is a correct conclusion.</u>

Nataly_w [17]2 years ago
3 0

Answer:

One more transformation – a horizontal stretch – would map ΔDCE onto ΔABE. So the triangles are similar.

Step-by-step explanation:

Rigid transformation involves the applications of some processes and procedures to change the orientation of a given figure. It can either be reflection, translation or rotation. While dilation is the process of resizing a given figure as required.

A horizontal stretching is a transformation that involves changing the position or coordinates of a point along the horizontal axis away from the vertical axis.

Lennox claims he used a sequence of rigid transformations and dilation, but did not perform one more transformation, horizontal stretch, which would make the two triangles to be similar.

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APEX HELP ASAP!!!!
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<span>1. The two boats picked for the trip are the steamboat and the tall ship. Let us assume that we will take the steamboat going to the island, and then we will take the tall ship for the return trip. We will then relate the distances travelled by both ships to each other.

2. We know that the steamboat takes five hours to complete the trip. The tall ship takes more time, at ten hours to complete the trip. We do not have the exact speeds of the steamboat or of the tall ship, but we do know that the tall ship is 10 knots slower than the steamboat. We likewise do not know the exact distance travelled by either ship, but we do know that both travel the same distance. We want to find out how fast each boat travels. We expect the answers to be in knots, with a difference of 10.

3. We know that distance is equivalent to the product of speed of a boat multiplied by the time of travel. For the trip going to the island, we will use the steamboat. Let its speed be x knots (equivalent to x nautical miles per hour), and let the distance going to the island be d nautical miles. Given that the time takes is 5 hours, this means that d = 5x.

4. If we let x be the speed of the boat you are taking to the island (the steamboat), then we know that the speed of the other boat (the tall ship) is 10 knots less than the steamboat's. So the speed of the tall ship (for the return trip) is (x - 10) knots.

5. Similar to part 3: we will multiply speed by time to determine the distance from the island. From part 4, we have determined that the speed of the tall ship to be used in returning is (x - 10) knots. Meanwhile, the given in the problem says that the tall ship will take 10 hours to make the trip. Therefore the distance will be equal to d = 10(x - 10) = 10x - 100 nautical miles.

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5x = 10x - 100

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8. We determined in part 4 that the speed of the second boat (in our case, the tall ship) is (x - 10) knots. Since we have calculated in part 7 that the steamboat travels at x = 20 knots, then the speed of the tall ship is (x - 10) = 20 - 10 = 10 knots.</span>
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2 years ago
James has t toy cars and Paul has 13 more. How many cars will James have if Paul gives him half of his cars?
Setler [38]

James will end up with his original t cars and half of (t+13) cars, so will have ...

... t + (t+13/2) = (3t +13)/2 . . . . cars James has after Paul's gift

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2 years ago
In a class, 4/5 of the students have mathematical instruments. 1/4 of these students have lost their protractors. What fraction
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Answer:

\frac{11}{20}

Step-by-step explanation:

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\frac{11}{20}

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2 years ago
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A treasure map says that a treasure is buried so that it partitions the distance between a rock and a tree in a 5:9 ratio. Marin
djyliett [7]

Answer:

A)  (7.6, 8.8)

which are the coordinates of the treasure.

Missing Problem Statement:

Given Options:

A) (11.4, 14.2)

B) (7.6, 8.8)

C) (5.7, 7.5)

D) (10.2, 12.6)

I have added the picture showing the traced map onto a coordinate plane to find exact location of treasure.

The coordinates of Tree are (16,21)

Coordinates of rock are (3,2)

Step-by-step explanation:

Let,

Coordinates of treasure be (a,b)

d_{1}= distance from tree to treasure

d_{2}=distance from rock to treasure

d_{1}=\sqrt{(16-x)^2 + (21-y)^2}

d_{2}=\sqrt{x\2 + (y-2)^2}

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which will be used to locate the treasure.

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d_{2}= 14.8, d_{1}= 8.2,

\frac{d_{2}}{ d_{1}}= 1.8

Check (C) (5.7, 7.5)

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Check (D) (10.2, 12.6)

d_{2}= 12.8, d_{1}= 10.2,

\frac{d_{2}}{ d_{1}}= 1.25

Check (B) (7.6, 8.8)

d_{2}= 8.2, d_{1}= 14.8,

\frac{d_{2}}{ d_{1}}= 0.55

Which satisfies Equation 1, such that ratio between rock and tree is 5:9 or  \frac{d_{2}}{ d_{1}}=\frac{5}{9}= 0.55

So, the coordinates of the treasure are (B) (7.6, 8.8)

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