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tankabanditka [31]
2 years ago
7

The mean gross annual incomes of certified welders are normally distributed with the mean of $20,000 and a standard deviation of

$2,000. The ship building association wishes to find out whether their welders earn more or less than $20,000 annually. The alternate hypothesis is that the mean is not $20,000. If the level of significance for this two-tailed test is 0.10, what is/are the critical value(s)
Mathematics
1 answer:
grandymaker [24]2 years ago
3 0

Answer:

At the 0.10 level of significance the z table gives critical values of -1.645 and 1.645 for two-tailed test.

Step-by-step explanation:

We are given that the mean gross annual incomes of certified welders are normally distributed with the mean of $20,000 and a standard deviation of $2,000.

The ship building association wishes to find out whether their welders earn more or less than $20,000 annually.

<u><em>Let </em></u>\mu<u><em> = mean gross annual incomes of certified welders</em></u>

So, Null Hypothesis, H_0 : \mu = $20,000    

Alternate hypothesis, H_A : \mu \neq $20,000

Here, null hypothesis states that the mean income of welders is equal to $20,000.

On the other hand, alternate hypothesis states that the mean income of welders is not $20,000.

Also, the test statistics that would be used here is <u>One-sample z test</u> <u>statistics</u> as we know about the population standard deviation;

                              T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean income

            \sigma = population standard deviation = $2,000

            n = sample size

Now, at the 0.10 level of significance the z table gives critical values of -1.645 and 1.645 for two-tailed test.

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