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vagabundo [1.1K]
2 years ago
6

The average annual cost of the first year of owning and caring for a large dog is $1,843 (US News and World Report, September 9,

2013). The Irish Red and White Setter Association of America has requested a study to estimate the annual first-year cost for owners of this breed. A sample of 50 will be used. Based on past studies, the population standard deviation is assumed known with σ ? = $255. a. What is the margin of error for a 95% confidence interval of the mean cost of the first year of owning and caring for this breed (to 2 decimals)? b. The DATAfile Setters contains data collected from fifty owners of Irish Setters on the cost of the first year of owning and caring for their dogs. Use these data sets to compute the sample mean (to 2 decimals). Using this sample, what is the 95% confidence interval for the mean cost of the first year of owning and caring for an Irish Red and White Setter (to 2 decimals)?
Mathematics
1 answer:
ICE Princess25 [194]2 years ago
7 0

Answer:

a. Error is 0.14

b. between 1913.68 to 1772.32

Step-by-step explanation:

Requirement a)

The margin of error is a statistic expressing the amount of random sampling error in a survey's results.

Given,

Size of the sample n = 50

We know, At 95% confidence interval,

The margin of error,

= 0.98/√n  

= 0.98/√50

= 0.98/7.07

= 0.13859 ~ 0.14

So the margin of error at 95% confidence level is 0.14.

Requirement b)

Given,

Standard deviation σ = 255

Population mean z = 1814

Size of the sample n = 50

We know, At 95% confidence interval,

(z-µ)/(σ/√n)  < Z_0.05

= - Z_0.05 < (z-µ)/(σ/√n) < Z_0.05

= - 1.96 * σ/√n < (z-µ)/(σ/√n)*  σ/√n  < 1.96 * σ/√n  [ in two tail Z test the value of Z_0.05 is 1.96 ]

= - 1.96 * 255/√50 < Z-µ <  1.96 * 255/√50

= -70.6828 < Z-µ < 70.6828

= 70.6828 > µ - Z > -70.6828

= 70.6828 + Z > µ > -70.6828 + Z

= 70.6828 + 1814 > µ > -70.6828 + 1814

=1913.68 > µ > 1772.32

So, the sample mean would be between 1913.68 to 1772.32.

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Edgar ran eee meters per second, and Mathieu ran mmm meters per second. The boys ran for ttt seconds.
Oksana_A [137]

Answer:

The expression showing how many more meters Mathieu ran than Edgar ran during that time is  t(m-e).

Step-by-step explanation:

Edgar ran 'e' meters per second, and Mathieu ran 'm' meters per second. The boys ran for 't' seconds.

The expression t(m-e) describes how many more meters Mathieu ran than Edgar ran during that time.

We can also use the expression tm-te represent the same quantity.

We know that,

\text{Distance} =\text{Speed}\times \text{Time}

Distance covered by Edgar = te

Distance covered by Mathieu = tm

Difference in distance d= tm - te=t(m-e)

The expression showing how many more meters Mathieu ran than Edgar ran during that time is  t(m-e).

7 0
2 years ago
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A cake has a mass of 2.5kg. It contains 275g of fruit. What percentage of fruit is there in the cake
Travka [436]
The answer is:  "11 %" . 
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There is 11% of fruit in the cake.
______________________________
Explanation:
____________________________________

275g is what percent of 2.5 kg?  

First, convert "275 g" into "kg".

Note the exact conversion:  1000 g = 1 kg .  

So 275 g = (275/1000) kg  = 0.275 kg .


0.275 kg = (n/100) * 2.5 kg ; 

→ (n/100) * 2.5 = 0.275 ;
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Divide each side by "(2.5)" 
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→ (n/100) = (0.275) / (2.5) ;

→ (n/100) = 0.11 ;

Multiply each side by "100" ; 

n = 11 . 
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2 years ago
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. A high school currently has a 30% dropout rate. They’ve been tasked to decrease that rate by 20%. Find the equivalent percenta
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Answer:

The equivalent percentage point drop = 10%

Step-by-step explanation:

The percentage point change is the difference between the final and initial values.

The percentage change is the difference between the final and initial values

divided by the initial value

It is required to decrease the dropout rate from 30% to 20%

The point change = 20 - 30 = -10 (-ve change ⇒ decrease)

The percentage change = \frac{10}{30}*100 = 33.33_%%

So, the equivalent percentage point drop = <u>10%</u>

And the percentage change = <u>33.33%</u>

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2 years ago
The time it takes a printer to print a job is an Exponential random variable with the expectation of 12 seconds. You send a job
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Answer:

0.8753

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Here, The third job will be ready for 10:01 AM, then E(Y)=61/12

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For the diagram below figure b is a reflection of y=2x of the line y =x
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The equation of the line would be y = (1/2)x.

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