All categories

1 year ago

Edgar ran eee meters per second, and Mathieu ran mmm meters per second. The boys ran for ttt seconds.

Mathematics

2 answers:

Oksana_A [137]1 year ago

7 0

Answer:

The expression showing how many more meters Mathieu ran than Edgar ran during that time is $t(m-e)$ .

Step-by-step explanation:

Edgar ran 'e' meters per second, and Mathieu ran 'm' meters per second. The boys ran for 't' seconds.

The expression $t(m-e)$ describes how many more meters Mathieu ran than Edgar ran during that time.

We can also use the expression $tm-te$ represent the same quantity.

We know that,

$\text{Distance} =\text{Speed}\times \text{Time}$

Distance covered by Edgar = te

Distance covered by Mathieu = tm

Difference in distance $d= tm - te=t(m-e)$

The expression showing how many more meters Mathieu ran than Edgar ran during that time is $t(m-e)$ .

Sveta_85 [38]1 year ago

4 0

Answer:

TE, then tm, then m-e, then t

Step-by-step explanation:

I got it right on khan academy

You might be interested in

Natalia is writing a recursive formula to represent the sequence 8,12,18,27 what value should she use as the common ratio in the

Marrrta [24]

Common ratio = second term / first term = 12 / 8 = 1.5

7 0

2 years ago

Read 2 more answers

Triangle A B C is shown. Angle A C B is a right angle. The length of hypotenuse A B is 12 centimeters, the length of C B is 9.8

Dafna11 [192]

Step-by-step explanation:

yo digo que es eso la verdad no se

3 0

2 years ago

Read 2 more answers

Happy is four times as old as Grumpy. The sum of their age is 100. How old are Happy and<br> Grumpy?

lys-0071 [83]

Answer:

grumpy is 20 happy is 80

Step-by-step explanation:

5 0

1 year ago

Read 2 more answers

A rectangular parcel of land is 70 ft longer than it is wide. Each diagonal between opposite corners is 130 ft. What are the dim

Bingel [31]

We have the following dimensions:
w=wide
w+70=length

We have a right triangle:
leg₁=w
leg₂=w+70
hypotenuse=130

Pythagoras theorem:
leg₁²+leg₂²=hypotenuse²
Then:

w²+(w+70)²=130²

We have to solve that equation:
w²+(w+70)²=130²
w²+w²+140w+4900=16900
2w²+140w+4900-16900=0
2w²+140w-12000=0
(2w²+140w-12000)/2=0/2
w²+70w-6000=0

w=(-70⁺₋√(4900+24000)) / 2
=(-70⁺₋170) / 2
We have two possible solutions:
Solution 1

w=(-70-170)/2=-120 (this solution is not possible because the result is negative and it have no sense in this problem).

Solution 2

w=(-70+170)/2=50 (this is the right solution)

w=50
w+70=120

ANSWER: the length would be 120 u (u=units of length ) and the wide would be 50 u.

5 0

2 years ago

You are considering the purchase of a closed circuit TV monitoring system for your store. The quarterly physical inventory has s

Tcecarenko [31]

If quarterly shrinkage (every 3 months) is 2.5%, then multiplying by $875,495 gives a value of 21887.38, or an average monthly shrinkage of 21887.38 / 3 = $7,295.79.For an employee to monitor the CCTV, it would cost ($7.5/h)(11 h/d)(30 d/m) = $2,475/month. Therefore, it is much cheaper (around 2/3 cheaper) to have an employee monitor CCTV rather than to allow the high shrinkage rate.

7 0

2 years ago