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NikAS [45]
2 years ago
8

A rectangular piece of paper has a width that is 3 inches less than its length. It is cut in half along a diagonal to create two

congruent right triangles with areas of 44 square inches. Which statements are true? Check all that apply.
Mathematics
1 answer:
yarga [219]2 years ago
7 0

Answer:

A is TRUE (44 in²*2=88 in²)

B is FALSE x(x-3)=88 (the rectangle) or x(x-3)/2=44 (the triangle)

C is TRUE if x(x-3)=88==>x²-3x-88=0

D is TRUE :

x²-3x-88=0

Δ=9+4*88=361=19²

==>x= 11 or x=-8 (excluded for <0)

E is FALSE for 11*4≠88

Step-by-step explanation:

correct me if i am wrong

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Ampicillin 250 mg IM every 12 hours is ordered. After reconstitution, there's 125 mg/mL. How many mL would you give?
Vanyuwa [196]

Answer:

Correct choice is C. 2 mL.

Step-by-step explanation:

Given that Ampicillin 250 mg IM every 12 hours is ordered. After reconstitution, there's 125 mg/mL. Now we need to find about how many mL would you give.

Let number of ml needed = x.

Since ratio of mg per mL will be fixed so we get equation:

\frac{mL}{mg}=\frac{x}{250}=\frac{1}{125}

\frac{x}{250}=\frac{1}{125}

x=\frac{1}{125} \times 250

x=\frac{250}{125}

x=2

Hence correct choice is C. 2 mL.

4 0
2 years ago
A silicon chip is 14 nanometers thick. A nanometer is equal to 0.000000001 meter. Express the thickness of the chip using scient
oksano4ka [1.4K]

Answer:

1.4 × 10^-8

Step-by-step explanation:

The chip is 14  nanometers

14 * .000000001

.000000014

Move the decimal 8 places to the right, because we need 1 number in front of the decimal for scientific notation.  The exponent will be -8 because  we moved it 8 places to the right

1.4 × 10^-8

4 0
2 years ago
Read 2 more answers
#6) Beth saved a total of $30 per month for her first car. Beth saved
cluponka [151]

Answer:

1) The domain In interval notation is [0, 20]

2) The range in interval notation is [100, 700]

Step-by-step explanation:

The given parameters are;

The amount Beth saved per month = $30

The number of months Beth saved = 20 months

The amount with which Beth opened her account = $100

Therefore, the amount of money Beth saved with respect to time is given as follows;

Y = $100 + $30 × X

Where;

Y = The amount of money Beth saved

X = The time (number of months) Beth saved

The domain is given as follows;

\{X | \ 0 \leq X \leq 20 \}

The domain in interval notation is [0, 20]

For the range, when X = 0, Y = $100

When X = 20, Y = $100 + $30 × 20 = $700

Therefore, the range is given as follows;

\{Y | \ 100 \leq Y \leq 700 \}

Which the range in interval notation is [100, 700].

6 0
2 years ago
A quality control engineer tests the quality of produced computers. suppose that 5% of computers have defects, and defects occur
11111nata11111 [884]
(a) 0.059582148 probability of exactly 3 defective out of 20

 (b) 0.98598125 probability that at least 5 need to be tested to find 2 defective.

  (a) For exactly 3 defective computers, we need to find the calculate the probability of 3 defective computers with 17 good computers, and then multiply by the number of ways we could arrange those computers. So

 0.05^3 * (1 - 0.05)^(20-3) * 20! / (3!(20-3)!)

 = 0.05^3 * 0.95^17 * 20! / (3!17!)

 = 0.05^3 * 0.95^17 * 20*19*18*17! / (3!17!)

 = 0.05^3 * 0.95^17 * 20*19*18 / (1*2*3)

 = 0.05^3 * 0.95^17 * 20*19*(2*3*3) / (2*3)

 = 0.05^3 * 0.95^17 * 20*19*3

 = 0.000125* 0.418120335 * 1140

 = 0.059582148

  (b) For this problem, let's recast the problem into "What's the probability of having only 0 or 1 defective computers out of 4?" After all, if at most 1 defective computers have been found, then a fifth computer would need to be tested in order to attempt to find another defective computer. So the probability of getting 0 defective computers out of 4 is (1-0.05)^4 = 0.95^4 = 0.81450625.

 The probability of getting exactly 1 defective computer out of 4 is 0.05*(1-0.05)^3*4!/(1!(4-1)!)

 = 0.05*0.95^3*24/(1!3!)

 = 0.05*0.857375*24/6

 = 0.171475

 
 So the probability of getting only 0 or 1 defective computers out of the 1st 4 is 0.81450625 + 0.171475 = 0.98598125 which is also the probability that at least 5 computers need to be tested.
3 0
2 years ago
Multiply and simplify.
qaws [65]

15x^2y^4z^2 will be your answer please thank me and friend me


3 0
2 years ago
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