Answer:
This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
A = 84 mg
Answer:
854
Step-by-step explanation:
1000/15=66
1000-66-80=854
(-3x + 15) + (-3x + 2)
Simplify by combining like terms.
-6x + 17
-6x + 17