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Likurg_2 [28]
2 years ago
9

If cos f° = four ninths and the measure of segment XW is 16 units, what is the measure of segment XY?

Mathematics
1 answer:
Alexus [3.1K]2 years ago
6 0

Answer:

D. 36 units

Step-by-step explanation:

The description of the triangle is:

<em>triangle XYW in which angle W is a right angle, angle X measure f degrees, and angle Y measures d degrees </em>

Therefore, side XY is adjacent to f and side XY is the hypotenuse

From definition:

cos(f) = adjacent/hypotenuse

Replacing:

cos(f) = XW/XY

4/9 = 16/XY

XY = 16*9/4

XY = 36 units

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Step-by-step explanation:

Han is multiplying10x^4 by 0.5^3 and gets 5x^7 is not a polynomial because 0.5 is not an integer. What is the error in han’s thinking explain

On multiplying 10x⁴ by 0.5x³,

10x^4\times 0.5x^3=(10\times 0.5)x^{4+3}\\\\=5x^7

A polynomial is a combination of coefficients and variables. It is made up of one or more monomial. Han says that it is not a polynomial because 0.5 is not an integer. The statement is false. After multiplication we get 5x⁷. It has a variable x and constant 5. Hence, its is a polynomial.

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A construction company is considering submitting bids for contracts of three different projects. The company estimates that it h
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Answer:

a.P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

b. E(x) = 0.3

c. S(x)=0.5196

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Step-by-step explanation:

The probability that the company won x bids follows a binomial distribution because we have n identical and independent experiments with a probability p of success and (1-p) of fail.

So, the PMF of X is equal to:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

Where p is 0.1 and it is the chance of winning. Additionally, n is 3 and it is the number of bids. So the PMF of X is:

P(x)=\frac{3!}{x!(3-x)!}*0.1^{x}*(1-0.1)^{n-x}\\

For binomial distribution:

E(x)=np\\S(x)=\sqrt{np(1-p)}

Therefore, the company can expect to win 0.3 bids and it is calculated as:

E(x) = np = 3*0.1 = 0.3

Additionally, the standard deviation of the number of bids won is:

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P(1)=\frac{3!}{1!(3-1)!}*0.1^{1}*(1-0.1)^{3-1}=0.243\\P(2)=\frac{3!}{2!(3-2)!}*0.1^{2}*(1-0.1)^{3-2}=0.027\\P(3)=\frac{3!}{3!(3-3)!}*0.1^{3}*(1-0.1)^{3-3}=0.001

So, the expected profit for the company is equal to:

E=-10,000+50,000(0.243)+100,000(0.027)+150,000(0.001)\\E=5,000

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