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2 years ago

14

Holly throws a 12-sided number solid with faces labeled 1 through 12. What is the probability that Holly will roll a number grea

ter than 12? Enter your answer in the box.

2 answers:

enyata [817]2 years ago

5 0

Answer:

0

Step-by-step explanation:

stepladder [879]2 years ago

4 0

Answer:

0

Step-by-step explanation:

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En las competencias de atletismo hay 120 participantes; 30 en la prueba de 100 m, 50 en la de 200 m y 40 en la carrera de relevo

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Answer:

120 by the questiom we have tl do plus or not

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2 years ago

Write the expanded form of h(3k-12.4)

ExtremeBDS [4]

Answer:3hk - 12.4h

Step-by-step explanation:

h(3k-12.4)

h x 3k - h x 12.4

3hk - 12.4h

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2 years ago

Ritika bought 5 meters of cloth from the market. She cut off 2 3/4 meters and gave it to Aditi. What length of cloth is left wit

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Answer:

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2 years ago

A weatherman stated that the average temperature during July in Chattanooga is 80 degrees or less. A sample of 32 Julys is taken

baherus [9]

Answer:

The correct set of hypotheses is

$H_{0}$ : d=80 degrees

$H_{0}$ : d>80 degrees

Step-by-step explanation:

The weatherman claims that the average temperature during July in Chattanooga is 80 degrees or less. To test this claim, following hypotheses need to be taken:

Let d be the the average temperature during July in Chattanooga, then

$H_{0}$ : d=80 degrees

$H_{0}$ : d>80 degrees

7 0

2 years ago

The word geometry has eight letters. three letters are chosen at random. what is the probability that two consonants and one vow

olga nikolaevna [1]

Answer:

0.536 is the required probability.

Step-by-step explanation:

We have been given the word the word "GEOMETRY"

we have to find the probability that two consonants and one vowel are chosen:

Number of consonants are: 5

Number of vowels are: 3

Hence, The required probability is: $\frac{^5C_2\cdot ^3C_1}{^8C_3}$

Using: $^nC_r=\frac{n!}{(r!)(n-r)!}$

$\frac{\frac{5!}{3!\cdot 2!}\cdot\frac{3!}{1!\cdot 2!}}{\frac{8!}{3!\cdot 5!}}$

Simplifying the above expression:

$\frac{\frac{5\cdot 4\cdot 3!}{3!\cdot 2}\cdot {\frac{3\cdot 2!}{2!}}}{\frac{8\cdot 7\cdot 6\cdot 5!}{5!\cdot 3\cdot 2}}$

Further simplification after cancelling out the common terms we get:

$\Rightarrow \frac{30}{56}=\frac{15}{28}=0.5357=0.536$

Hence, Option 1 is correct.

4 0

2 years ago

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