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Romashka [77]
2 years ago
11

The word geometry has eight letters. three letters are chosen at random. what is the probability that two consonants and one vow

el are chosen? 0.536 0.268 0.179 0.089
Mathematics
2 answers:
pickupchik [31]2 years ago
5 0

Answer:

A on 2020 edg

Step-by-step explanation:

olga nikolaevna [1]2 years ago
4 0

Answer:

0.536 is the required probability.

Step-by-step explanation:

 We have been given the word the word "GEOMETRY"

we have to find the probability that two consonants and one vowel are chosen:

Number of consonants are: 5

Number of  vowels are: 3

Hence, The required probability is: \frac{^5C_2\cdot ^3C_1}{^8C_3}

Using: ^nC_r=\frac{n!}{(r!)(n-r)!}

\frac{\frac{5!}{3!\cdot 2!}\cdot\frac{3!}{1!\cdot 2!}}{\frac{8!}{3!\cdot 5!}}

Simplifying the above expression:

\frac{\frac{5\cdot 4\cdot 3!}{3!\cdot 2}\cdot {\frac{3\cdot 2!}{2!}}}{\frac{8\cdot 7\cdot 6\cdot 5!}{5!\cdot 3\cdot 2}}

Further simplification after cancelling out the common terms we get:

\Rightarrow \frac{30}{56}=\frac{15}{28}=0.5357=0.536

Hence, Option 1 is correct.


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