Answer: 64 years
Step-by-step explanation:
Let assume the dealer sold the bottle now for $P, then invested that money at 5% interest. The return would be:
R1 = P(1.05)^t,
This means that after t years, the dealer would have the total amount of:
$P×1.05^t.
If the dealer prefer to wait for t years from now to sell the bottle of wine, then he will get the return of:
R2 = $P(1 + 20).
The value of t which will make both returns equal, will be;
R1 = R2.
P×1.05^t = P(1+20)
P will cancel out
1.05^t = 21
Log both sides
Log1.05^t = Log21
tLog1.05 = Log21
t = Log21/Log1.05
t = 64 years
The best time to sell the wine is therefore 64years from now.
The probability that a child with a speaking part is chosen randomly would be 2:5.
D a theorem needs to be proven
Answer:
11 over 13
Step-by-step explanation:
first, you deal with multiplication;
x = -12 + 14 - 12x + 13
second, deal with addition;
x = -2 - 12x + 13
third, take -12 to the other side then the negative changes to positive;
12x + x = -2 + 13
fourth, add them then simplify;
13x = 11
ans is 11 over 13
Hi there!
Let's assume that one month is represented by the variable 'm', the amount of minutes you started with is 's', and minutes you spent is 'p'.
So, one month can be represented as 'm=s-p'.
The next month is a bit more tricky. This will incorporate 75 less minutes into the equation. 'm=s-75' can be used to represent this, as we assume that you didn't use any minutes in the first month, and that p=75 in this case.
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