This problem can be expressed through the equation:
x+3x+10= 90
To solve it we subtract 10 on both sides
→x+3x=80
Add x and 3x
→4x=80
And divide each side by 4
→x=80/4
→x=20
ANSWER:
20
Answer:
Hello your question is incomplete attached below is the complete question
Ix = 0 Ux = 
Iz = 0 Uz = 
Iy = 5 Uy = 10
Step-by-step explanation:
Ix = 0 Ux =
Iz = 0 Uz =
Iy = 5 Uy = 10
attached below is the detailed solution
34/100
= 0.34
3 tenths, 4 hundreths
Printer A
y = 14x
Printer B
Time(min) | 3 | 5 | 8 | 12 |
Pages printed | 48 | 80 | 128 | 192 |
Printer A prints 14(1) = 14 pages per minute.
Printer B prints 48/3 = 16 pages per minute.
The printer that prints at a faster rate is printer B.
Answer:
1. 15
2. 8
Step-by-step explanation:
The two sequence are geometric progression GP, because they follow a constant multiple (common ratio)
The nth term of a GP is;
Tn = ar^(n-1)
Where;
a = first term
r = common ratio
For the first sequence;
The common ratio r is
r = T3/T2 = 540/90 = 6
r = 6
T2 = ar^(2-1) = ar
T2 = 90 = ar
Substituting the values of r;
90 = a × 6
a = 90/6
a = 15
First term = 15
2. The sam method applies here.
Common ratio r = T3/T2 = 128/32 = 4
r = 4
T2 = ar^(2-1) = ar
T2 = 32 = ar
Substituting the values of r;
32 = a × 4
a = 32/4
a = 8
First term = 8
