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Ainat [17]
1 year ago
10

Mckenzie has enough paint to paint 108 square feet. She wants to paint her garage door, which has a height of 12 feet. The garag

e door is in the shape of a rectangle. If McKenzie has just enough paint to cover the garage door, what is the width of the door?
Mathematics
1 answer:
Lelu [443]1 year ago
7 0

Area of a rectangle = Length x width.

Replacing the values you are given:

108 = 12 x width

Width = 108 / 12

Width = 9 feet.

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Which geometric solids would model the tent? O Cone and sphere Cylinder and cone O Pyramid and rectangular prism Triangular pris
joja [24]

Answer:

Triangular prism and rectangular prism

Step-by-step explanation:

shapes

7 0
1 year ago
One similar figure has an area that is nine times the area of another. The larger figure must have dimensions that are times the
frutty [35]
T<span>he area of a figure is the measure of the extent of a two dimensional figure which is usually measured as the square units of the dimensions of the figure.

For example, given a figure with dimensions, say k, the area of the figure is given by k^2.
</span>
<span>Given that o<span>ne similar figure has an area that is nine times the area of another.

Since the two figures are similar, it means that there areas will be proportional as their dimensions will be proportional.

Let the dimensions of the smaller figure be k and the larger figure is p times the smaller figure. Then the area of the smaller figure is k^2 and the area of the larger figure is (pk)^2.

Now, given that the area of the larger figure is nine times the area of the smaller figure, this means that:
\frac{(pk)^2}{k^2} = \frac{9}{1}  \\  \\  \frac{p^2k^2}{k^2} =9 \\  \\ p^2=9 \\  \\ p= \sqrt{9}  \\ \\ p=3
</span>
Therefore, the larger figure must have dimensions that are 3 times the dimensions of the smaller figure.</span>
3 0
1 year ago
Read 2 more answers
Farmer John walks his pet pig around his barn every day. The barn is 25
kkurt [141]

Answer:

900m

Step-by-step explanation:

A=wl

W=25

L=12

A=25 x 12

A= 300

300 meters x 3 laps = 900 meters walked

4 0
1 year ago
A high school coach needs to buy new athletic shorts for the 15 members of the basketball team. The coach must spend less than $
Studentka2010 [4]

Answer:

15x < 200; x < 13.33; the maximum price for a pair of shorts

Step-by-step explanation:

1. Set up the inequality

Let x = price of a pair of shorts. Then

 15x = price of shorts for the team

You have one condition:

15x < 200

2. Solve the inequality

\begin{array}{rcl}15x & < & 200\\\\x & < & \dfrac{200}{15}\\\\x & < & \mathbf{13.333}\\\end{array}

3. Meaning of solution

The solution represents the maximum price the coach can pay for a pair of shorts.

If the coach pays $13.33 per pair, the total cost for the team will be $199.95, and the condition is satisfied.

4 0
2 years ago
Read 2 more answers
Suppose that Kevin can choose to get home from work by car or bus. When he chooses to get home by car, he arrives home after 7 p
astraxan [27]

Answer:

The approximate probability that Kevin chose to get home from work by bus, given that he arrived home after 7 pm = 0.838

Step-by-step explanation:

Let the probability that Kevin arrives home after 7 pm be P(L)

Probability that Kevin uses the bus = P(B)

Probability that Kevin uses the car = P(C)

Probability of arriving home after 7 pm if the car was taken = P(L|C) = 4% = 0.04

Probability of arriving home after 7 pm if the bus was taken = P(L|B) = 15% = 0.15

The bus is cheaper, So, he uses the bus 58% of the time.

P(B) = 58% = 0.58

P(C) = P(B') = 1 - P(B) = 1 - 0.58 = 0.42

The approximate probability that Kevin chose to get home from work by bus, given that he arrived home after 7 pm = P(B|L)

The conditional probability P(A|B) is given mathematically as

P(A|B) = P(A n B) ÷ P(B)

Hence, the required probability, P(B|L) is given as

P(B|L) = P(B n L) ÷ P(L)

But we do not have any of P(B n L) and P(L)

Although, we can obtain these probabilities from the already given probabilities

P(L|C) = 0.04

P(L|B) = 0.15

P(B) = 0.58

P(C) = 0.42

P(L|C) = P(L n C) ÷ P(C)

P(L n C) = P(L|C) × P(C) = 0.04 × 0.42 = 0.0168

P(L|B) = P(L n B) ÷ P(B)

P(L n B) = P(L|B) × P(B) = 0.15 × 0.58 = 0.087

P(L) = P(L n C) + P(L n B) = 0.0168 + 0.087 = 0.1038 (Since the bus and the car are the two only options)

The approximate probability that Kevin chose to get home from work by bus, given that he arrived home after 7 pm

= P(B|L) = P(B n L) ÷ P(L)

P(B n L) = P(L n B) = 0.087

P(L) = 0.1038

P(B|L) = (0.087/0.1038) = 0.838150289 = 0.838

Hope this Helps!!!

8 0
2 years ago
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