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slamgirl [31]
2 years ago
7

A least squares regression line: a. may be used to predict a value of y if the corresponding x value is given b. implies a cause

-effect relationship between x and y c. can only be determined if a good linear relationship exists between x and y d. None of these alternatives is correct.
Mathematics
1 answer:
seraphim [82]2 years ago
3 0

Answer:

a) May be used to predict a value of y if the corresponding x value is given

Step-by-step explanation:

In regression analysis, the vertical distance from the regression line to the data points can be minimized using the least square regression line.

Given the example of a least square regression equation:

y = ax + b

Where

a = slope

b = Y-intercept

If the value of x is known, the value of y may be predicted.

Option A is correct.

A least squares regression line may be used to predict a value of y if the corresponding x value is given

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Show a way to count from 170 to 410 using tens and hundreds. circle at least 1 benchmark number
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Benchmark are numbers that are used as standards to which the rest of the data is compared to. When counting numbers using a number line, the benchmark numbers are the intervals written on the axis. For benchmark numbers of 10, the number line on top of the attached picture is shown. Starting from 170, the tick marks are added by 10, such that the next numbers are 180, 190, 200, and so on and so forth. When you want to find 410, just find the benchmark number 410.

The same applies to benchmark numbers in intervals of 100. If you want to find 170, used the benchmark numbers 100 and 200. Then, you estimate at which point represents 170. For 410, you base on the benchmark numbers 400 and 500.

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In circle E, and are diameters. Angle BCA measures 53°. Circle E is shown. Line segments A C and B D are diameters. Lines are dr
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Step-by-step explanation:

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2 years ago
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Arthur borrowed $2,100 from the bank. 3 years later, Arthur owes the bank $2,478. What was the percentage rate of simple interes
ASHA 777 [7]

Answer:

Percentage Rate=6%

Step-by-step explanation:

Total borrowed=$2,100

Time=3 years

Rate=?

Total amount owed after 3 years= total borrowed + simple interest

$2,478=$2,100 + x

X=$2,478 - $2,100

=$378

The simple interest=$378

Simple interest=P×R×T

Where,

P= principal=$2,100

R=Rate=?

T=Time=3 years

Simple interest=$378

Simple interest=P×R×T/100

$378=$2,100×R×3/100

$378=$6,300R/100

$378=$63R

R=$378/$63

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Therefore,

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A car insurance company suspects that the younger the driver is, the more reckless a driver he/she is. They take a survey and gr
erastovalidia [21]

Answer:

The confidence interval for the difference in proportions is

-0.028\leq p_1-p_2 \leq 0.096

No. As the 95% CI include both negative and positive values, no proportion is significantly different from the other to conclude there is a difference between them.

Step-by-step explanation:

We have to construct a confidence interval for the difference of proportions.

The difference in the sample proportions is:

p_1-p_2=x_1/n_1-x_2/n_2=(183/217)-(322/398)=0.843-0.809\\\\p_1-p_2=0.034

The estimated standard error is:

\sigma_{p_1-p_2}=\sqrt{\frac{p_1(1-p_1)}{n_1}+\frac{p_2(1-p_2)}{n_2} } \\\\\sigma_{p_1-p_2}=\sqrt{\frac{0.843*0.157}{217}+\frac{0.809*0.191}{398} } \\\\\sigma_{p_1-p_2}=\sqrt{0.000609912+0.000388239}=\sqrt{0.000998151} \\\\ \sigma_{p_1-p_2}=0.0316

The z-value for a 95% confidence interval is z=1.96.

Then, the lower and upper bounds are:

LL=(p_1-p_2)-z*\sigma_p=0.034-1.96*0.0316=0.034-0.062=-0.028\\\\\\UL=(p_1-p_2)+z*\sigma_p=0.034+1.96*0.0316=0.034+0.062=0.096

The confidence interval for the difference in proportions is

-0.028\leq p_1-p_2 \leq 0.096

<em>Can it be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group?</em>

No. It can not be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group, as the confidence interval include both positive and negative values.

This means that we are not confident that the actual difference of proportions is positive or negative. No proportion is significantly different from the other to conclude there is a difference.

8 0
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