All categories

2 years ago

Everglades National Park is 225 mi long. What scale is needed to draw a map of Everglades National Park that is 10 in. long?

Mathematics

1 answer:

shusha [124]2 years ago

7 0

Answer:

A. 1 in. = 22.5 mi

Step-by-step explanation:

Since 22.5 x 10 = 225, we can conclude that this will fit the scale needed. B. is incorrect because it is simply illogical in context with a scale and the question. C. is incorrect since 10 x 0.04 is 0.4, which does not equal 10. D. is incorrect since we need the scale to add up to equal 225 mi, not 22.5.

Hope this helps!

You might be interested in

The Chang's neighbor owns a ready-mix company. The company receives an order for 12.5 cubic yards of concrete. This mixture of c

ella [17]

The quantities in the proportion you give add to 16 pounds, of which 2 pounds are cement. That is, cement constitutes 1/8 of the total weight.

For each yard of concrete, 4000 lb/8 = 500 lb of cement are used.

For 12.5 yards of concrete, 12.5 * 500 = 6,250 pounds of cement will be used.

_____
"yard" in this case is shorthand for "cubic yard".

3 0

2 years ago

Sterre charges $35 to file tax returns, but files for free if she only needs the easiest form. Then she donates $2 to clean wate

borishaifa [10]

We have been given that Sterre charges $35 to file tax returns, but files for free if she only needs the easiest form. Also, she donates $2 to clean water projects per tax return she files.

Further we know that Sterre charged $7,245 and made a donation of $1,242 this year for the tax returns she filed.

Let x be the number of free income tax returns and y be the number of $35 income tax returns.

Therefore, we can set up:

$0\times x+35\times y=7245\Rightarrow 35y=7245\Rightarrow y=\frac{7245}{35}=207$

Since she donates $2 for each return that she files, therefore, we can set up:

$2(x+y)=1242\Rightarrow x+y=621\Rightarrow x+207=621\Rightarrow x=414$

Therefore,

Sterre filed 414 tax returns for free and filed 207 tax returns for $35.

7 0

2 years ago

FILIPINO 10

Serjik [45]

Step-by-step explanation:

Pabula- ang pabula ay nang galing sa English world na parable na nang galing namn sa Greek world na parabol na ang ibig sabihin na maiksing sanaysay.

Emento-ang mga Elemento na ma tag puan sa parabulang kwento at banghay ng kwento.

Nilalaman-ang nilalaman ng parabula ay tungkol sa isang katiwala na nag lulustay ng ari-arian sa kanyang amo.

Kakanyahan-ang kakanyahan ng parabula ang tusong katiwala ay ang pagtitiwala at pag taksil.

!! Yan napo sana nakakatulong po!!

4 0

2 years ago

A sociologist recorded the estimated life expectancies of women born in Center City. Use the data from women born in 1970 and 20

ANEK [815]

Y = 0.213x – 352.0 <span> represents this linear model shown in the data table.
Plug in the values of x into the equation for a double check.
Let's try 1980.

</span><span>y = 0.213(1980) – 352.0
</span>y = 69.74
which is closest to the 70.1 whereas other options do not satisfy the condition.

6 0

2 years ago

Read 2 more answers

A machine produces parts that are either defect free (90%), slightly defective (3%), or obviously defective (7%). Prior to shipm

AURORKA [14]

Answer:

(a) 0.0686

(b) 0.9984

Step-by-step explanation:

Given that a machine produces parts that are either defect free (90%), slightly defective (3%), or obviously defective (7%).

Let A, B, and C be the events of defect-free, slightly defective, and the defective parts produced by the machine.

So, from the given data:

P(A)=0.90, P(B)=0.03, and P(C)=0.07.

Let E be the event that the part is disregarded by the inspection machine.

As a part is incorrectly identified as defective and discarded 2% of the time that a defect free part is input.

So, $P\left(\frac{E}{A}\right)=0.02$

Now, from the conditional probability,

$P\left(\frac{E}{A}\right)=\frac{P(E\cap A)}{P(A)}$

$\Rightarrow P(E\cap A)=P\left(\frac{E}{A}\right)\times P(A)$

$\Rightarrow P(E\cap A)=0.02\times 0.90=0.018\cdots(i)$

This is the probability of disregarding the defect-free parts by inspection machine.

Similarly,

$P\left(\frac{E}{A}\right)=0.40$

and $\Rightarrow P(E\cap B)=0.40\times 0.03=0.012\cdots(ii)$

This is the probability of disregarding the partially defective parts by inspection machine.

$P\left(\frac{E}{A}\right)=0.98$

and $\Rightarrow P(E\cap C)=0.98\times 0.07=0.0686\cdots(iii)$

This is the probability of disregarding the defective parts by inspection machine.

(a) The total probability that a part is marked as defective and discarded by the automatic inspection machine

$=P(E\cap C)$

$= 0.0686$ [from equation (iii)]

(b) The total probability that the parts produced get disregarded by the inspection machine,

$P(E)=P(E\cap A)+P(E\cap B)+P(E\cap C)$

$\Rightarrow P(E)=0.018+0.012+0.0686$

$\Rightarrow P(E)=0.0986$

So, the total probability that the part produced get shipped

$=1-P(E)=1-0.0986=0.9014$

The probability that the part is good (either defect free or slightly defective)

$=\left(P(A)-P(E\cap A)\right)+\left(P(B)-P(E\cap B)\right)$

$=(0.9-0.018)+(0.03-0.012)$

$=0.9$

So, the probability that a part is 'good' (either defect free or slightly defective) given that it makes it through the inspection machine and gets shipped

$=\frac{\text{Probabilily that shipped part is 'good'}}{\text{Probability of total shipped parts}}$

$=\frac{0.9}{0.9014}$

$=0.9984$

(c) The probability that the 'bad' (defective} parts get shipped

=1- the probability that the 'good' parts get shipped

=1-0.9984

=0.0016

5 0

2 years ago