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Oksana_A [137]
2 years ago
12

Answer for 701 km -523 km 445m

Mathematics
1 answer:
alexira [117]2 years ago
8 0
701-523=178
Not sure if that's what you're asking but 
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At a particular restaurant, each onion ring has 45 calories and each slider has 325 calories. A combination meal with onion ring
AlladinOne [14]

Answer:

There were 6 onion rings and 2 slider in the combination meal.

Step-by-step explanation:

Let x be the number of onion rings and y be the number of slider.

Calories in one onion ring = 45 calories

Calories in one slider = 325 calories

Total number of calories = 920

Thus, we can write the equation:

45x + 325y = 920

There are 3 times as many onion rings as the sliders.

Thus, we can write the equation:

x = 3y

Solving the two equation by substitution method, we get,

45(3y) + 325y = 920\\460y = 920\\y = 2\\x = 3y = 3(2) = 6

Thus, there were 6 onion rings and 2 slider in the combination meal.

7 0
2 years ago
i will mark as brainiest Jared is using a 100 ft rope to set up a kite-shaped area for food vendors. He has started roping off t
blsea [12.9K]

Sample Response: A kite has two pairs of congruent adjacent sides and opposite sides that are not congruent. Jared has already created one pair of congruent adjacent sides. Since he has used 60 ft of rope, there are 40 ft remaining. This means that he will need 20 ft of rope for each of the other sides, or half of the remaining rope, in order to create another pair of congruent adjacent sides. Since this is a different length than 30 ft, the shape has opposite sides that are not congruent.


4 0
2 years ago
Read 2 more answers
The swimming instructor has a list of 152 students who have signed up for swimming lessons. The swimming instructor can register
andrew-mc [135]

Answer:

2. 13

Step-by-step explanation:

The least number of classes need for all of the students to be registered in a class is 13 since you want all of the stuednts to be registered so no one should be left out. If we do 12*12 (12 students in each class and there are 12 classes), that would only let 144 students take the swimming classes and 8 students would be left out. We don't want that though since we want all of the students to be registered. So let's go to 12*13 (12 students in each class and  there are 13 classes), that would let 156 students take the swimming class. 156>152 so therefore, 13 classes would allow for all 152 students to be registered and it is the least number of classes needed for all the students to be registered in a class (plus you would have 4 seats left for anyone who wants to register in the future but the remainder doesn't matter).  

6 0
2 years ago
During his science experiment, Yuri measured the temperature of a water sample as 24 degrees Celsius. To determine the temperatu
mr Goodwill [35]

Answer:

75.2 degrees Fahrenheit

Step-by-step explanation:

F =  StartFraction 9 Over 5 EndFraction C + 32

  • Substitute 24 for C.
  • Multiply the value of C by StartFraction 9 Over 5 EndFraction before adding 32.
  • 24 Degrees Celsius is 75.2 Degrees Fahrenheit.

8 0
2 years ago
Read 2 more answers
Consider a tank in the shape of an inverted right circular cone that is leaking water. The dimensions of the conical tank are a
Artyom0805 [142]

Answer:

\frac{dh}{dt} = \frac{216}{1875\pi}

Step-by-step explanation:

Given

Represent radius with r and height with h

h = 12ft

r = 10ft

Rate = \frac{8ft^3}{min} when h = 10ft

Express radius in terms of height

\frac{r}{h} = \frac{10}{12}

\frac{r}{h} = \frac{5}{6}

r = \frac{5}{6}h

First, we need to determine the volume of the cone in terms of height.

Volume = \frac{1}{3}\pi r^2h

Substitute r = \frac{5}{6}h

V = \frac{1}{3} * \pi * (\frac{5}{6}h)^2 * h

V = \frac{1}{3} * \pi * \frac{25}{36}h^2 * h

V = \frac{1}{3} * \pi * \frac{25}{36}h^3

V = \frac{25}{108} \pi h^3

Differentiate both sides w.r.t time (t)

\frac{dV}{dt} = 3 *  \frac{25}{108} \pi h^{3-1} * \frac{dh}{dt}

\frac{dV}{dt} = \frac{75}{108} \pi h^{2} \frac{dh}{dt}

Solve for \frac{dh}{dt}

\frac{dh}{dt} = \frac{dv}{dt} * \frac{108}{75\pi h^2}

At this point, h = 10 and \frac{dv}{dt} = \frac{8ft^3}{min}

So, we have:

\frac{dh}{dt} = 8 * \frac{108}{75\pi 10^2}

\frac{dh}{dt} = \frac{8 * 108}{75\pi 10^2}

\frac{dh}{dt} = \frac{864}{7500\pi}

\frac{dh}{dt} = \frac{216}{1875\pi}

Hence:

The rate is \frac{216}{1875\pi} ft/min

6 0
2 years ago
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