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Stels [109]
2 years ago
9

A drinks company use 76.8 kg of sugar in April .How much sugar the day use each day?​

Mathematics
2 answers:
Strike441 [17]2 years ago
4 0

Answer:

2.56 kgs

Step-by-step explanation:

76.8kg ÷ 30 days = 2.56 kgs

Korvikt [17]2 years ago
3 0
<h3>SoLuTiOn☞</h3>

Amount of sugar used - 76.8 kg

No. Of Days in Month of April - 30 days

∴ Sugar used each day is = 76.8 ÷ 30

76.8 \div 30 \\  \\  =  \frac{76.8}{30}  \\  \\ =   \frac{768}{30 \times 10}  \\  \\ =   \frac{ \cancel{768}}{ \cancel{30} \times 10} \fbox{cancelling by 3} \\  \\  =  \frac{256}{10 \times 10}  \\  \\  =  \frac{256}{100}  \\  \\  = 2.56 \: kg

<h3>So <u>2.56 kg</u> is used <u>everyday</u>.</h3>

<h2>Hope This Helps You </h2>

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The smaller rectangle was scaled by a factor of 2 to produce the larger figure. use the drop-down menus to show the missing dime
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Jason wanted to place all 540 marbles in the 3 newly bought boxes. If he wants to
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The first box will have 90 marbles, the second 180 and the third 270.

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On a coordinate plane, 2 polygons are shown. Polygon A B C D has points (1, negative 6), (5, negative 6), (6, negative 2), and (
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Answer:

The correct option is;

Use a scale factor of 2

Step-by-step explanation:

The parameters given are;

A = (1, -6)

B = (5, -6)

C = (6, -2)

D = (0, -2)

A'' = (1.5, 4)

B'' = (3.5, 4)

C'' = (4, 2)

D'' = ( 1, 2)

We note that the length of side AB in polygon ABCD = √((5 -1)² + (-6 - (-6))²) = 4

The length of side A''B'' in polygon A''B''C''D'' = √((3.5 -1.5)² + (4 - 4)²) = 2

Which gives;

AB/A''B'' = 4/2 = 2

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The length of side B''C'' in polygon A''B''C''D'' = √((4 -3.5)² + (2 - 4)²) = (√17)/2

Also we have;

The length of side CD in polygon ABCD = √((6 -0)² + (-2 - (-2))²) = 6

The length of side C''D'' in polygon A''B''C''D'' = √((4 -1)² + (2 - 2)²) = 3

For the side DA  and D''A'', we have;

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Therefore the Polygon A B C D can be obtained from polygon A''B''C''D'' by multiplying each side of polygon A''B''C''D'' by 2

The correct option is therefore;

Use a scale factor of 2.

3 0
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