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Stels [109]
1 year ago
9

A drinks company use 76.8 kg of sugar in April .How much sugar the day use each day?​

Mathematics
2 answers:
Strike441 [17]1 year ago
4 0

Answer:

2.56 kgs

Step-by-step explanation:

76.8kg ÷ 30 days = 2.56 kgs

Korvikt [17]1 year ago
3 0
<h3>SoLuTiOn☞</h3>

Amount of sugar used - 76.8 kg

No. Of Days in Month of April - 30 days

∴ Sugar used each day is = 76.8 ÷ 30

76.8 \div 30 \\  \\  =  \frac{76.8}{30}  \\  \\ =   \frac{768}{30 \times 10}  \\  \\ =   \frac{ \cancel{768}}{ \cancel{30} \times 10} \fbox{cancelling by 3} \\  \\  =  \frac{256}{10 \times 10}  \\  \\  =  \frac{256}{100}  \\  \\  = 2.56 \: kg

<h3>So <u>2.56 kg</u> is used <u>everyday</u>.</h3>

<h2>Hope This Helps You </h2>

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Explanation:

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The horizontal velocity is constant, so Vx = V₀x

ii) Vertical component:

V₀y = V₀ sin α

The vertical component is linear with acceleration = g ≈ 9.8 m/s²

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3) Displacement equations

i) Horizontal displacment:

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ii) Vertical displacement:

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4) Solution

i) x = V₀ cosα t = V₀ cos(32°) t = 2.00 m ← salmon starts 2.00m from a waterfall

⇒ V₀ = 2 / [cos(32°) t ]

ii) y = V₀ sin α t - 4.9 t² = V₀ sin(32°) t - 4.9 t²

iii) Replace V₀ with 2 / [cos(32°) t ]

y = sin(32°) × 2 / [cos(32°) t ] × t - 4.9t² = 2 tan(32°) - 4.9t²

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V₀ = 2 / [cos(32°) (0.38) ] = 6.2 m/s

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Answer:

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For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.

We will apply the formula

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It becomes

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The upper end of the confidence interval is 25000 + 245 = 25245

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