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Stels [109]
2 years ago
9

A drinks company use 76.8 kg of sugar in April .How much sugar the day use each day?​

Mathematics
2 answers:
Strike441 [17]2 years ago
4 0

Answer:

2.56 kgs

Step-by-step explanation:

76.8kg ÷ 30 days = 2.56 kgs

Korvikt [17]2 years ago
3 0
<h3>SoLuTiOn☞</h3>

Amount of sugar used - 76.8 kg

No. Of Days in Month of April - 30 days

∴ Sugar used each day is = 76.8 ÷ 30

76.8 \div 30 \\  \\  =  \frac{76.8}{30}  \\  \\ =   \frac{768}{30 \times 10}  \\  \\ =   \frac{ \cancel{768}}{ \cancel{30} \times 10} \fbox{cancelling by 3} \\  \\  =  \frac{256}{10 \times 10}  \\  \\  =  \frac{256}{100}  \\  \\  = 2.56 \: kg

<h3>So <u>2.56 kg</u> is used <u>everyday</u>.</h3>

<h2>Hope This Helps You </h2>

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Sholpan [36]

Answer:

6 2/3 mL

Step-by-step explanation:

Multiply thru by 100 to get:

1000 + 60x = 30*40 + 30x

30x = 200

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A blouse that regularly sells for 28.50 is on sale for one third what is the sale prices
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1 year ago
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sweet-ann [11.9K]

Answer:

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Step-by-step explanation:

6 0
1 year ago
Which statement about the simplified binomial expansion of (a + b)", where n is a positive integer, is true?
Alja [10]

Answer:

(a+b)^n  ={n \choose 0}a^{(n)}b^{(0)} + {n \choose 1}a^{(n-1)}b^{(1)} + {n \choose 2}a^{(n-2)}b^{(2)} + .....  +{n \choose n}a^{(0)}b^{(n)}

Step-by-step explanation:

The Given question is INCOMPLETE as the statements are not provided.

Now, let us try and solve the given expression here:

The given expression is: (a +b)^n, n > 0

Now, the BINOMIAL EXPANSION is the expansion which  describes the algebraic expansion of powers of a binomial.

Here, (a+b)^n  = \sum_{k=0}^{n}{n \choose k}a^{(n-k)}b^{(k)}

or, on simplification, the terms of the expansion are:

(a+b)^n  ={n \choose 0}a^{(n)}b^{(0)} + {n \choose 1}a^{(n-1)}b^{(1)} + {n \choose 2}a^{(n-2)}b^{(2)} + .....  +{n \choose n}a^{(0)}b^{(n)}

The above statement holds for each  n > 0

Hence, the complete expansion for the given expression is given as above.

4 0
2 years ago
Read 2 more answers
Marty and Ethan both wrote a function, but in different ways.
marishachu [46]

<em><u>Question:</u></em>

Marty and Ethan both wrote a function, but in different ways.

Marty

y+3=1/3(x+9)

Ethan

x y

-4 9.2

-2 9.6

0 10

2 10.4

Whose function has the larger slope?

1. Marty’s with a slope of 2/3

2. Ethan’s with a slope of 2/5

3. Marty’s with a slope of 1/3

4. Ethan’s with a slope of 1/5

<em><u>Answer:</u></em>

Marty’s with a slope of 1/3 has the larger slope

<em><u>Solution:</u></em>

<em><u>Given that Marty equation is:</u></em>

y + 3 = \frac{1}{3}(x+9)

<em><u>The point slope form is given as:</u></em>

y - y_1 = m(x-x_1)

Where, "m" is the slope of line

On comapring both equations,

m = \frac{1}{3}

<em><u>Ethan wrote a function:</u></em>

Consider any two values from the table we have;

(0, 10) and (2, 10.4)

<em><u>The slope is given by formula:</u></em>

m = \frac{y_2-y_1}{x_2-x_1}

From above two points,

(x_1, y_1) = (0, 10)\\\\(x_2, y_2) = (2, 10.4)

Therefore,

m = \frac{10.4-10}{2-0}\\\\m = \frac{0.4}{2} \\\\m = 0.2

Thus we get,

\text{Slope of Ethan} < \text{Slope of Marty}

Therefore, Marty’s with a slope of 1/3  has the larger slope

4 0
2 years ago
Read 2 more answers
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