Two <em>possible answers</em> are:
5/16 and 3/8.
Explanation:
To create a fraction equivalent to a given fraction, you multiply the numerator and denominator by the same number. This means for 5/8, we could have:
5/8; (5*2)/(8*2)=10/16; (5*3)/(8*3)=15/24; etc.
For 1/2, we could have:
1/2; (1*2)/(2*2)=2/4; (1*3)/(2*3)=3/6; etc.
ΔACB and ΔMNB are similar. Therefore the corresponding sides are in proportion:
Substitute:
Answer:
The area of the sumo wrestling ring is 
Step-by-step explanation:
The circumference of the circular sumo wrestling ring is 
, that means its radius 
is:
Now once we have the radius of the sumo wrestling ring we can find its area 
by the following formula:
Putting in the value of 
we get:
Therefore the area of the sumo wrestling ring is 
Vineet can conclude that:
B ) the system of equations does not have a solution.
Given:
2 parallelograms with an area of 9 1/3 yd²
height of each parallelogram is 1 1/3 yd
Area of parallelogram = base * height
We need to divide the combined area into two to get each parallelogram's base.
9 1/3 = ((9*3)+1)/3 = 28/3
28/3 ÷ 2 = 28/3 * 1/2 = 28/6 yd² or 4 4/6 yd² ⇒ 4 2/3 yd²
Area of each parallelogram is 4 2/3 yd²
4 2/3 yd² = base * 1 1/3 yd
14/3 yd² ÷ 4/3 yd = base
14/3 yd² x 3/4 yd = base
14*3 / 3*4 = base
42 / 12 = base
3 6/12 yd = base
or 3 1/2 yd = base
a) the base of each parallelogram is 3 1/2 yards
b) we can assume that the two parallelograms form a rectangle.
area of a rectangle is length times width.
length is 3 1/2 yds * 2 = 7 yds
width is 3 1/2 yds
Area of rectangle = 7 yds * 3 1/2 yds
Area = 7 yd * 7/2 yd
Area = 7*7 / 2 yd²
Area = 49 / 2 yd²
Area = 24 1/2 yd²
