Please Help Me!!! I'm Being Timed!!! What is -2(3x+12y-5-17x-16y+4) simplified?

The function below shows the number of car owners f(t), in thousands, in a city in different years t: f(t) = 0.25t^2 - 0.5t + 3.

Bingel [31]

The average rate of change (m) is the ratio of the change in function value to the width of the interval:
m = (f(6) - f(2))/(6 - 2)

To compute this, we need to compute f(6) and f(2).
f(6) = (0.25*6 -0.5)*6 +3.5 = 9.5
f(2) = (0.25*2 - 0.5)*2 +3.5 = 3.5
Then the average rate of change is
m = (9.5 - 3.5)/(6 - 2) = 6/4 = 1.5

The average rate of change is 1.5 thousand owners per year.

3 0

2 years ago

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While Flinn was starting the fire, his friends were collecting firewood. Flinn has 5 sticks. If he puts 3 sticks in the fire eve

fomenos

Answer:

Time required to make a pile of 45 sticks next to their fire = 10 minutes

Step-by-step explanation:

This is an example of arithmetic progression.

First term = 5 - 3 + 7 = 9 sticks

Common difference = 7 - 3 = 4 sticks.

So the number of sticks next to their fire is increasing like this

9, 13, 17, 21 .............

$n^{th}$ term of AP = a + (n-1) d, we need to find n

a + (n-1) d = 45

9 + (n-1) x 4 = 45

(n-1) x 4 = 36

n - 1 = 9

n = 10

Time required to make a pile of 45 sticks next to their fire = 10 minutes

4 0

2 years ago

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Which linear equation represents on the graph

s2008m [1.1K]

Remember, rise/run is the easiest way to determine slope

y=mx+b is form

mx is slope, whilst b is y int

so, answer? y=-3x-2

Or A.

4 0

2 years ago

A supervisor records the repair cost for 17 randomly selected stereos. A sample mean of $66.34 and standard deviation of $15.22

expeople1 [14]

Answer:

Critical value: T = 1.337

The 80% confidence interval for the mean repair cost for the stereos is between $45.991 and $86.689

Step-by-step explanation:

We have the standard deviation for the sample. So we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 17 - 1 = 16

80% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 16 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.8}{2} = 0.9$ . So we have T = 1.337, which is the critical value