Solve 3kx + 24 = 9kx for x.<br> A. x= 4/k<br> B. x= -2/k<br> C. x= 2/k<br> D. x= -4/k

In right triangle ABC, mC - 90° and AC BC. Which trigonometric ratio is cquivalent to sin b?

vaieri [72.5K]

Answer:

All trigonometric Ratios are $SinB = \frac{AC}{AB}$ , $SinA= \frac{CB}{AB}$ , $CosA= \frac{AC}{AB}$

And $Cos B = \frac{CB}{AB}$ .

Step-by-step explanation:

Given that,

A right angle triangle ΔABC, ∠C =90°.

Diagram of the given scenario shown below,

In triangle ΔABC :-

$Hypotenuse = AB\\Base = CB\\Perpendicular = AC$

So, $Sin\theta = \frac{perpendicular}{hypotenuse}$

$SinB = \frac{AC}{AB}$

Now, for ∠A the dimensions of trigonometric ratios will be changed.

Here the base for ∠A is AC , perpendicular side is CB and hypotenuse will be same for all ratios.

$SinA= \frac{CB}{AB}$

Again, $Cos\theta= \frac{base}{hypotenuse}$

Then, $CosA= \frac{AC}{AB}$

And $Cos B = \frac{CB}{AB}$ .

Hence,

All trigonometric Ratios are $SinB = \frac{AC}{AB}$ , $SinA= \frac{CB}{AB}$ , $CosA= \frac{AC}{AB}$

And $Cos B = \frac{CB}{AB}$ .

8 0

2 years ago

If f(x)=x2+10sinx, show that there is a number c such that f(c)=1000.

gayaneshka [121]

F(x) is continuous for all x.

Pick a point and show that f(x) is either negative or positive. Pick another point and show that f(x) is negative, if positive, or positive, if negative.

At x = 30, f(30) - 1000 = 900 + 10sin(30) - 1000 ≤ 0
Now, show at another point f(x) - 1000 is positive, and hence, there would be root between 30 and such point.

Let's pick 40.
At x = 40, f(40) - 1000 = 1600 + 10sin(40) - 1000 ≥ 0

Since f(x) - 1000 is continuous, there lies a root between 30 and 40, and hence, 30 ≤ c ≤ 40

7 0

2 years ago

70.18 divided by 0.9 round the answer to the nearest hundredth

storchak [24]

Answer:

77.98

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

When planning a party you want to know whom to invite. Among the people you would like to invite are three touchy friends.You kn

harkovskaia [24]

Answer:

Jasmine only.

Jasmine and Kanti only.

No one.

Step-by-step explanation:

There is no possible way to invite all three friends.

Since both Samir and Kanti will not attend if someone else is not invited, Jasmine is the only friend that can be invited on her own:

One person: Jasmine.

When inviting two people, if Jasmine is invited, Samir can't be invited and Kanti will only attend if Jasmine also does. Therefore, Jasmine and Kanti can go together and there is no way Kanti can be invited.

Two people: Jasmine and Kanti.

Furthermore, if nobody is invited, no one will be unhappy.

5 0

2 years ago

The mean weight of newborn infants at a community hospital is 6.6 pounds. A sample of seven infants is randomly selected and the

Lera25 [3.4K]

Answer:

The correct option is A

Step-by-step explanation:

From the question we are told that

The population is $\mu = 6.6$

The level of significance is $\alpha = 5\% = 0.05$

The sample data is 9.0, 7.3, 6.0, 8.8, 6.8, 8.4, and 6.6 pounds

The Null hypothesis is $H_o : \mu = 6.6$

The Alternative hypothesis is $H_a : \mu > 6.6$

The critical value of the level of significance obtained from the normal distribution table is

$Z_{\alpha } = Z_{0.05 } = 1.645$

Generally the sample mean is mathematically evaluated as

$\=x = \frac{\sum x_i }{n}$

substituting values

$\=x = \frac{9.0 + 7.3 + 6.0+ 8.8+ 6.8+ 8.4+6.6 }{7}$

$\=x = 7.5571$

The standard deviation is mathematically evaluated as

$\sigma = \sqrt{\frac{\sum [ x - \= x ]}{n} }$

substituting values

$\sigma = \sqrt{\frac{ [ 9.0-7.5571]^2 + [7.3 -7.5571]^2 + [6.0-7.5571]^2 + [8.8- 7.5571]^2 + [6.8- 7.5571]^2 + [8.4 - 7.5571]^2+ [6.6- 7.5571]^2 }{7} }$ $\sigma = 1.1774$