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Troyanec [42]
2 years ago
15

a garden plot is to contain 240 sq. ft. if its length is to be 3 times its width,what should its dimensions be?

Mathematics
1 answer:
Nastasia [14]2 years ago
3 0
W^2=80
W SQRT80
W=8.94 ANS.FOR THE WIDTH
L=3*8.94=26.83 ANS.FOR THE LENGTH
PROOF:
240=8.94*26.83
240=240

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The Naturally Made Bath and Body store pays $550 a month for rent and utilities. The average cost for its products to be manufac
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Answer:

220 products need to be sold to break it even.

Step-by-step explanation:

550 + 3.00x = 5.50x

550 = 2.50x

220 = x

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The median of $20, x, 15, 30, 25$ is $0.4$ less than the mean. If $x$ is a whole number, what is the sum of all possible values
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198

Step-by-step explanation:

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2 years ago
What is the value of b and the missing symbol in Jamilla’s inequality?
Sindrei [870]

Answer:

b=1, \geq

Step-by-step explanation:

we know that

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Observing the graph

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x\geq 1 and x\leq -3

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assume the symbol of the first solution and then compare the results

\left|x+b\right|\ge2

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Second solution (case negative)

-(x+b)\ge2

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(x+b)\leq-2

substitute the value of b and compare the results

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x\leq-3 -------> is correct

4 0
2 years ago
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Find the average value of the function f(x, y, z) = 5x2z 5y2z over the region enclosed by the paraboloid z = 4 − x2 − y2 and the
S_A_V [24]
The paraboloid meets the x-y plane when x²+y²=9. A circle of radius 3, centre origin. 

<span>Use cylindrical coordinates (r,θ,z) so paraboloid becomes z = 9−r² and f = 5r²z. </span>

<span>If F is the mean of f over the region R then F ∫ (R)dV = ∫ (R)fdV </span>

<span>∫ (R)dV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] rdrdθdz </span>

<span>= ∫∫ [θ=0,2π, r=0,3] r(9−r²)drdθ = ∫ [θ=0,2π] { (9/2)3² − (1/4)3⁴} dθ = 81π/2 </span>


<span>∫ (R)fdV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] 5r²z.rdrdθdz </span>

<span>= 5∫∫ [θ=0,2π, r=0,3] ½r³{ (9−r²)² − 0 } drdθ </span>

<span>= (5/2)∫∫ [θ=0,2π, r=0,3] { 81r³ − 18r⁵ + r⁷} drdθ </span>

<span>= (5/2)∫ [θ=0,2π] { (81/4)3⁴− (3)3⁶+ (1/8)3⁸} dθ = 10935π/8 </span>

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3 0
2 years ago
You invested a total of $12,000 at 4.5 percent and 5 percent simple interest. During one year, the two accounts earned $570. How
Luda [366]

Answer: You invested $6000 in both accounts.

Step-by-step explanation:

Let x represent the amount invested in the account earning 4.5% interest.

Let y represent the amount invested in the account earning 5% interest.

You invested a total of $12,000 at 4.5 percent and 5 percent simple interest. This means that

x + y = 12000

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I = PRT/100

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P represents the principal

R represents interest rate

T represents time in years

I = interest after t years

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I = (x × 4.5 × 1)/100 = 0.045x

Considering the account earning 5%

I = (y × 5 × 1)/100 = 0.05y

During one year, the two accounts earned $570. . This means that

0.045x + 0.05y = 570 - - - - - - - - - - 1

Substituting x = 12000 - y into equation 1, it becomes

0.045(12000 - y) + 0.05y = 570

540 - 0.045y + 0.05y = 570

- 0.045y + 0.05y = 570 - 540

0.005y = 30

y = 30/0.005 = 6000

x = 12000 - y = 12000 - 6000

x = $6000

6 0
2 years ago
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