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2 years ago

Describe in words the surface whose equation is given. (assume that r is not negative.) θ = π/4

1 answer:

7 0

An equation in the form $\theta=\dfrac{\pi}{4}$ is the line
that goes through the origins and whose tangent equates $\dfrac{\pi}{4}$ . In general, any equation in the form $\theta=\theta_0$
is the equation of a line.

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Given: BC bisects DBE. Prove: ABD is congruent to ABE

Arada [10]

Answer:

See below

Step-by-step explanation:

BC bisects <DBE and if AC is a straight line then you have that:

<ABD + <DBC = 180 (straight angle because of line AC)

<ABE + <CBE = 180 ( straight angle because of line AC)

Because BC bisects <DBE => < DBC = <CBE

So <ABD and <ABE must be the same to both sum 180 when added < DBC

7 0

2 years ago

Elliott is counting the change from a class fundraiser. He has half as many quarters as nickels, and he has 7 fewer dimes than n

Akimi4 [234]

Answer: He should have translated the scenario as value of all dimes = value of all

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Find the range of y=3/2cos4x-1

MrRissso [65]

Answer:

Range = [- 2.5, 0.5] = [ - 5/2, 1/2]

Step-by-step explanation:

Smallest value of cos α = - 1,

largest value of cos α = 1.

When cos 4x = - 1, y=3/2cos4x-1 = 3/2*(-1) - 1 = - 5/2 = - 2 1/2 = - 2.5

When cos 4x = 1, y=3/2cos4x-1 = 3/2*1 - 1 = 1/2 = 0.5

Range = [- 2.5, 0.5] = [ - 5/2, 1/2]

5 0

2 years ago

The law of cosines is a2+b2-2abcosC=c2 find the value of 2abcosC

quester [9]

Isolating 2abCos(c) on one side of the equation and using the given values of a, b and c we can find the answer to this question as shown below:

$a^{2} + b^{2} -2ab*cos(C)=c^{2} \\ \\ 
2ab *cos(C)= a^{2} + b^{2} - c^{2} \\ \\ 
2ab *cos(C)=2^{2} + 2^{2}- 1^{2} \\ \\ 
2ab*cos(C) = 7$

7 0

2 years ago

Read 2 more answers

r. Yi buys vegetables at a market. He purchases 6 pounds of potatoes, p, and 3 pounds of onions, n, for $18. Onions cost twice a

ad-work [718]

Answer:

The equation 2n = p should be 2p = n.
The actual cost of the onions is $3.00 per pound.
Potatoes cost $1.50 per pound.

Step-by-step explanation:

The wording "onions cost twice as much as potatoes" is understood to mean the cost per pound of onions (n) is equal to two times the cost per pound of potatoes (2p). Then the appropriate equation would be ...

2p = n

Then the solution is ...

6p +3(2p) = 18

12p = 18

p = 18/12 = 1.50

n = 2p = 2(1.50) = 3.00

The equation should be 2p = n; onions cost $3.00 per pound; potatoes cost $1.50 per pound.

5 0

2 years ago