We have this following information
30-seconds ad = $146000
The manufacturer wants to use one slot of 30-second per segment
Total segment = 20 segment
Total campaign cost = 20×146000 = $2,920,000
solution:
The probability mass function for binomial distribution is,
Where,
X=0,1,2,3,…..; q=1-p
find the probability that (p∧ ≤ 0.06) , substitute the values of sample units (n) , and the probability of nonconformities (p) in the probability mass function of binomial distribution.
Consider x to be the number of non-conformities. It follows a binomial distribution with n being 50 and p being 0.03. That is,
binomial (50,0.02)
Also, the estimate of the true probability is,
p∧ = x/50
The probability mass function for binomial distribution is,
Where,
X=0,1,2,3,…..; q=1-p
The calculation is obtained as
P(p^ ≤ 0.06) = p(x/20 ≤ 0.06)
= 50cx ₓ (0.03)x ₓ (1-0.03)50-x
= (50c0 ₓ (0.03)0 ₓ (1-0.03)50-0 + 50c1(0.03)1 ₓ (1-0.03)50-1 + 50c2 ₓ (0.03)2 ₓ (1-0.03)50-2 +50c3 ₓ (0.03)3 ₓ (1- 0.03)50-3 )
=( ₓ (0.03)0 ₓ (1-0.03)50-0 + ₓ (0.03)1 ₓ (1-0.03)50-1 + ₓ (0.03)2 ₓ (1-0.03)50-2 ₓ (0.03)3 ₓ (1-0.03)50-3 )
we know that
In an Arithmetic Sequence the difference between one term and the next is a constant
This problem is an Arithmetic Sequence
where
the first term is 
and
the common difference is 
In general we can write an Arithmetic Sequence as a rule

where
a1 is the first term
d is the common difference
so

<u>Find the term a7</u>
![an=a1+d*(n-1)\\ \\ a7=23+(-2)*[7-1]\\ \\\\ a7=23-12\\ \\\\ a7=11](https://tex.z-dn.net/?f=%20an%3Da1%2Bd%2A%28n-1%29%5C%5C%20%5C%5C%20%20a7%3D23%2B%28-2%29%2A%5B7-1%5D%5C%5C%20%5C%5C%5C%5C%20a7%3D23-12%5C%5C%20%5C%5C%5C%5C%20%20%20%20a7%3D11%20%20%20%20%20)
therefore
<u>the answer is</u>

To solve this we are going to use the formula fro the force applied to a spring:

where

is the spring constant

is the extension
Since we know the

, we can replace that in our formula and solve for

:


where

is the acceleration

is the spring constant

is the extension

is the mass
We know for our problem that

,

, and

. So lets replace those values in our formula to find

:



We can conclude that the acceleration of the block when s=0.4m is

.
Answer:
5.75x10^11
Step-by-step explanation:
quotient of 2,300 and (0.4x10^-8) is
2,300 ÷ (0.4x10^-8)
2300 = 2.3x10^3
We now have
2.3x10^3 / 0.4x10^-8
= (2.3/0.4) x ( 10^(3 - (-8))
= 5.75 x (10^(3+8))
= 5.75 x (10^11)
= 5.75x10^11
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