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love history [14]
2 years ago
15

Seven students, A, B, C, D, E, F, and G, have been selected to be possible characters in a school play. Only 4 people will actua

lly be in the play. The narrowing of the field must obey the following rules: D can only be selected if G is selected. E cannot be selected unless B is selected. Either G or A must be selected, but not both. Either E or C must be selected, but not both. Which of the following, if selected for the show, will completely determine the makeup of the four on the show?
Mathematics
1 answer:
nadezda [96]2 years ago
8 0

if you pick G you don't have to pick D so I didn't I picked B so that I could pick E and they didn't say any rules about F so I picked G,B,E,F

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Find the volume of the following solid figure. Use = 3.14. V = 4/3r3. A sphere has a radius of 3.5 inches. Volume (to the neares
Juli2301 [7.4K]
To solve the problem shown above, you must apply the proccedure shown below:

 1. You must use tthe formula for calculate the volume of a sphere, which is:

 V=4πr³/3

 V is the volume of the sphere.
 r is the radius of the sphere (r=3.5 inches)

 2. When you susbstitute these values into the formula shown above, you obtain the volume of the sphere. Therefore, you have:

 V=4πr³/3
 V=4π(3.5 inches)³/3

 3. Therefore, the answer is:

 V=179.5 inches³
4 0
2 years ago
Read 2 more answers
The Parsons have a balance of $3,664.47 in their check register. On their bank statement, the balance on the account is $2,346.8
Lapatulllka [165]
$2,346.89 + $500 + $1,456.81 = $4,303.70

$4,303.70 - $324.56 - $25.50 - $78.92 - $30.25 - $60 - $60 - $60 = $3,664.47

$3,664.47 is exactly what they have in their checkbook.
5 0
2 years ago
A candy store sells caramels and milk chocolate by the pound the table below shows the total cost in dollars for a pound of each
MakcuM [25]

The cost of 1\frac{3}{4} pounds chocolate milk is $6.25 more than the cost of 1\frac{3}{4} pounds of Caramel.

Step-by-step explanation:

Given,

Cost of one pound of Caramels = $10.28

Cost of 1\frac{3}{4} pounds of Caramel = 10.28*1\frac{3}{4}

Cost of 1\frac{3}{4} pounds = 10.28*\frac{7}{4}=\frac{71.96}{4}= \$17.99

Cost of one pound of chocolate milk = $13.85

Cost of 1\frac{3}{4} pounds = 13.85*1\frac{3}{4}=13.85*\frac{7}{4}

Cost of 1\frac{3}{4} pounds = \frac{96.95}{4}=\$24.24

Difference = 24.24 - 17.99 = $6.25

The cost of 1\frac{3}{4} pounds chocolate milk is $6.25 more than the cost of 1\frac{3}{4} pounds of Caramel.

Keywords: difference, multiplication

Learn more about multiplication at:

  • brainly.com/question/10414011
  • brainly.com/question/10483199

#LearnwithBrainly

5 0
2 years ago
Mrs.williams is organizing her office supplies. There are 3 open boxes of paper clips in her desk drawer.each box has 7/8 of pap
Fantom [35]
21/8 or 2 and 5/8 boxes left
3 0
2 years ago
he amount of​ carbon-14 present in animal bones t years after the​ animal's death is given by ​P(t)equals=Upper P 0 e Superscrip
Murrr4er [49]

Answer:

t = 2489 years

Step-by-step explanation:

The equation you need for this is

N=N_{0}e^{kt}

where N is the amount AFTER the decomposition, N-sub-0 is the initial amount, k is the decomposition constant and t is time in years.

If we are told that the tusk LOST 26% of its carbon-14, that means <u>74% of it remains</u> from the <u>initial 100% it had</u>.

Filling in:

74=100e^{-.00012097t}

Begin by dividing both sides by 100 to get a decimal of .74:

.74=e^{-.00012097t}

The goal is to get that t out of the exponential position in which it is currently sitting.  Do this by "undoing" the e.  Do THAT by taking the natural log of both sides because a natural log "undoes" an e.  This is due to the fact that the base of a natural log is e.  

ln(.74)=ln(e^{-.00012097t})

The ln and the e disappear on the right side, leaving

ln(.74) = -.00012097t

Plug ln(.74) into your calculator to get

-.3011050928 = -.00012097t

t = 2489

4 0
2 years ago
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