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sdas [7]
2 years ago
10

Bill is considering taking out a loan. He estimates that he can afford monthly payments of $375 for 10 years in order to support

his loan. He finds that, with an APR of 6.5% compounded monthly, he can take a loan of $33,025.69.
Assuming that Bill's monthly payment and the length of the loan remain fixed, which of these statements is true about the size of the loan Bill could take if he received a different APR?


A. If the interest rate were 7.4%, the amount of the loan that Bill is considering taking out would be more than $33,025.69.

B. If the interest rate were 6.8%, the amount of the loan that Bill is considering taking out would be less than $33,025.69.

C. If the interest rate were 6.4%, the amount of the loan that Bill is considering taking out would be less than $33,025.69.

D. If the interest rate were 7.2%, the amount of the loan that Bill is considering taking out would be more than $33,025.69.
Mathematics
1 answer:
Anuta_ua [19.1K]2 years ago
4 0
For the same payment and term, the lower the interest rate, the more the loan can be. The opposite is also true. The appropriate selection is ...
  B. If the interest rate were 6.8%, the amount of the loan Bill is considering taking out would be less than $33,025.69.


_____
At 6.8%, Bill can afford a loan of $32,585.93.
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Alisiya [41]

Answer:

38%

Step-by-step explanation:

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Hopefully this helps you

4 0
2 years ago
a shopkeeper sold goods for rs 2400 and made a profit of 25% in the process. find his profit per cent if he had sold his goods f
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case 1,

Let the CP be ₹x,

SP = ₹2400

Profit = SP – CP

= 2400 – x

Profit % = {(2400–x)/ x} × 100%

According to the question,

{(2400–x)/ x} × 100 = 25

=> (2400–x)/ x= 25 /100

=> 100(2400–x) = 25x [ cross multiplication]

=> 240000 – 100x = 25x

=> 240000 = 25x + 100x

=> 240000 = 125x

=> 240000/125 = x

=> x = 1920

So, CP = ₹1920

case 2,

SP = ₹2040

Profit = SP – CP

= 2040 – 1920

= ₹120

profit % = 120/1920 × 100%

= 16%

<h3>Thus, his profit would be 16% if he had sold his goods for ₹2040.</h3>
6 0
2 years ago
A quantity with an initial value of 8600 grows exponentially at a rate of 20% every 2 minutes. What is the value of the quantity
Hatshy [7]

Answer:

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1872 : 12 = 156= the loss each month  

156/1872*100% = 8.33 % then round it

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