3x−8≤23 OR −4x+26≥6 solve for x

Mathematics

2 answers:

artcher [175]2 years ago

6 0

Answer:

x ≤ 31/3

the solution of the first inequality is, 3x-8 ≤ 23 is x ≤ 31/3

the solution to the second inequality, 4x+26 ≥ 6 is x ≤ 5

the union of the solutions of both inequalities is x ≤ 31/3

Mama L [17]2 years ago

5 0

Answer:

x ≤ 31/3

Step-by-step explanation:

You might be interested in

If e = 9 cm and f = 40 cm, what is the length of g?

rewona [7]

(9,40,41) is a Pythagorean Triple, farther down the list than teachers usually venture.

Answer: D. 41 cm

There's a subset of Pythagorean Triples where the long leg is one less than the hypotenuse,

a^2+b^2 = (b+1)^2

a^2 + b^2 = b^2 + 2b +1

a^2=2b+1

So we get one for every odd number, since the square of an odd number is odd and the square of an even number is even.

b = (a^2 - 1)/2

a=3, b=(3^2-1)/2=4, c=b+1=5

a=5, b=(5^2-1)/2 =12, c = 13

a=7, b=24, c=25

a=9, b=40, c=41

a=11, b=60, c=61

a=13, b=84, c=85

It's good to be able to recognize Pythagorean Triples when we see them.

Otherwise we'd have to work the calculator:

√(9² + 40²) = √1681 = 41

8 0

2 years ago

Jeremy opens a chocolate shop in the city. He pays $1,500 a month for rent and maintenance of the shop. The price of raw materia

KATRIN_1 [288]

Amount of money paid by Jeremy as rent and maintenance of shop per month = $1500
Cost of raw materials and manufacturing per month = $6000
Total cost that Jeremy has to spend per month = (1500 + 6000) dollars
      = 7500 dollars
Number of individual chocolates sold = 2400
Number of chocolates sold in boxes = 50 boxes
   = (12 * 50) chocolates
   = 600 chocolates
Then
Total number of chocolates sold by Jeremy = 2400 + 600
   = 3000
Now
Price of each chocolate = 7500/3000 dollars
   = 75/30 dollars
   = 5/2 dollars
   = 2.5 dollars
Price of 600 chocolates = 600 * (5/2) dollars
   = 300 * 5 dollars
   = 1500 dollars
Price of 12 chocolates = (1500/600) * 12
   = 15 * 2
   = 30 dollars
Then
We can say that each box of chocolate should be sold at $30. All the loose chocolates should be sold at $2.5 each.

8 0

2 years ago

Fez rolls 2 fair dice and adds the results from each. Work out the probability of getting a total less than 6.

Temka [501]

Answer:

The probability of getting sum of two dice is less than six

P(E) =0.25

Step-by-step explanation:

Step(i):-

The total number of cases n(S) = 6² = 36

Let 'E' be the event of getting sum of two dice is less than six

{(1,2) , (1,3),(1,4),(2,1),(2,2),(2,3),(3,1),(3,2),(4,1)}