Question

A student prepares 150.0 mL of 1.40 M HCl using 35.0 mL of a stock solution. What is the concentration of the stock solution? Use mc033-1.jpg. 0.327 M 4.29 M 6.00 M 7.35 M

Answer 1

Answer: The concentration of the stock solution will be 6.00 M.

Explanation: To calculate the molarity of the stock solution we use the formula:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the stock solution.

$M_2\text{ and }V_2$ are the molarity and volume of the HCl solution.

Given:

$M_1=?M\\V_1=35mL\\M_2=1.40M\\V_2=150mL$

Putting values in above equation, we get:

$M_1\times 35=1.40\times 150$

$M_1=6M$

So, the concentration of the stock solution is 6M.

Answer 2

Your answer would be c.6.00 M