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Irina-Kira [14]
2 years ago
13

The grocery store sells kumquats for $5.00 a pound and Asian pears for $3.25 a pound. Write an equation in standard form for the

weights of kumquats k and Asia pears p that a customer could buy with $18
Mathematics
2 answers:
Vsevolod [243]2 years ago
8 0

Answer:

Equation will be 5k + 3.25p = $18

Step-by-step explanation:

Price of kumquats per pound = $5.00

Price of Asian pears per pound = $3.25

Let the weight of kumquats be represented by = k

Let the weight of Asian pears be represented by = p

As asked, how much kumquats and pears can be bought in $18

The equation will be 5k + 3.25p = $18

aniked [119]2 years ago
3 0
Okay so your equation is going to be : 18= 5k + 3.25p
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Answer:

They are dependent because we have to select from people who are given cards.

Step By Step Explanation:

So we'll take away people not given cards first den find the probability of selecting people with cards over the total number of people present .

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Where C represent combination

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5 Adoncia makes a scale drawing of the front of
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Answer:

Since the length of the drawing is 200 ft. and equivalent to 13.33 in. with a scale of 15 ft to 1 in. and the length of the paper is 11 in., Adoncia's drawing will not fit on the sheet of paper

Step-by-step explanation:

The given parameters are;

The scale of the drawing is 15 ft = 1 in.

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Adoncia's drawing will not fit on the sheet of paper.

4 0
2 years ago
According to a "how to stop bullying" Web site, 15% of students report experiencing bullying one to three times within the most
AlekseyPX

Answer:

His 95% confidence interval is (0.065, 0.155).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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For this problem, we have that:

n = 186, \pi = 0.11

95% confidence level

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The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.11 - 1.96\sqrt{\frac{0.11*0.89}{186}} = 0.065

The upper limit of this interval is:

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His 95% confidence interval is (0.065, 0.155).

4 0
1 year ago
Jack works for a company that pays him $20 an hour. His normal workday does not exceed 8 hours. After working 8 hours in a day,
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If r is the midpoint of qs rs=2x-4, st= 4x-1 and rt = 8x-43 find qs
sammy [17]

Answer:

QS=68\ units

Step-by-step explanation:

step 1

Find the value of x

we know that

r is the midpoint of qs

so

QR=RS

QS=QR+RS------> QS=2RS -----> equation A

RT=RS+ST ----> equation B

see the attached figure to better understand the problem

Substitute the given values in the equation B and solve for x

8x-43=(2x-4)+(4x-1)

8x-43=6x-5

8x-6x=43-5

2x=38

x=19

step 2

Find the value of RS

RS=2x-4

substitute the value of x

RS=2(19)-4

RS=34\ units

step 3

Find the value of QS

Remember equation A

QS=2RS

so

QS=2(34)=68\ units

6 0
2 years ago
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