Marianne has been collecting donations for her biscuit stall at the school summer fayre. There are some luxury gift tins of bisc
uits to be sold at £5 each, normal packets at £1 each, and mini-packs of 2 biscuits at 10p each. She tells Amy that she has recieved exactly 100 donations in total, with a collective value of £100, amd that her stock of £1 packets is very low compared with the other items. Amy wants to work out how many of each item Marianne has. Show how she can do it.
The problem conditions give rise to 2 equations in 3 unknowns. Let L, M, N represent the number of Luxury, Mini, and Normal packets sold. .. L +M +N = 100 . . . . . . the number of packets sold .. 5L +0.1M +N = 100 . . the value of donations These result in the relationships .. L = (9/40)M .. N = 100 -(49/40)M
There are three integer solutions in which the numbers are non-negative. .. (L, M, N) = (0, 0, 100) or (9, 40, 51) or (18, 80, 2)
If Marianne sold 100 normal packets, her stock would be "very low" compared to the others.
If Marianne sold 51 normal packets, her stock may be "very low" with respect to the others, depending on how many of each she started with. This might be the solution if we require non-zero numbers of all packets were sold.
Answer: Hello! The answer to your question is B, the intersection of the lines drawn to bisect each vertex of the triangle. Hope this helped! Please pick my answer as the Brainliest!
To find the specification limit such that only 0.5% of the bulbs will not exceed this limit we proceed as follows; From the z-table, a z-score of -2.57 cuts off 0.005 in the left tail; given the formula for z-score (x-μ)/σ we shall have: (x-5000)/50=-2.57 solving for x we get: x-5000=-128.5 x=-128.5+5000 x=4871.50
Ok, so if the angle is 120 degrees, its one third of the full cake (which is 360 degrees). So the area of the whole circle (worked out with area = pi * r^2 where r is 30) gives 900*pi, and so one third of that (because her slice is one third) is 300pi.
