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Vinil7 [7]
2 years ago
10

Jenny is taking a vacation to Florida. She travels 70 kilometers per hour for 2 hours, and 63 kilometers per hour for 5 hours. O

ver the 7 hour time period what Jenny's average speed?
Mathematics
1 answer:
Helga [31]2 years ago
6 0
Jenny traveled 70 km/h over 2 hours and 63 km/h over 5 hours. Her travel time was a total of 7 hours. 

We need to find out how far she traveled during this 7-hour period.

70 km/h * 2 h = 140 km 
63 km/h * 5 h = 315 km

Then, we can add 140 km and 315 km to get a total distance traveled of <em>455 km/h.</em>

We were asked to find the average <em>speed.</em> We can find it now, since we have total distance traveled (455 km) and total time taken (7 hours).

Then, 
455km / 7h = 65 km/h.
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The population of a town can be modeled by the regression equation y = 20,000(1.03x). Which is the best prediction for the popul
bixtya [17]

Answer:

The best prediction for the population in year 25 is 41,876\ people

Step-by-step explanation:

we have a exponential function of the form

y=a(b^{x})

where

a is the initial value

b is the base

In this problem

a=20,000\ people

b=1.03

b=1+r

r=b-1=1.03-1=0.03

r=3\%

so

y=20,000(1.03^{x})

For x=25\ years

substitute

y=20,000(1.03^{25})

y=41,875.56\ people

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4 0
2 years ago
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The number of calls coming per minute into a hotel reservation center is Poisson random variable with mean 3.
natima [27]

Answer:

a) 0.05

b) 0.9826

c) 0.000039308

Step-by-step explanation:

a) P_X(0) = \frac{e^{-3}3^0}{0!} = e^{-3} =  0.05

b) For two minutes, the mean is doubled, hence it is 6. In order to calculate the probability of al least two calls arriving, we calculate first the probability of the complementary event: At most 1 call will arrive. For that probability, we need to sum the probabilities of 0 and 1.

P_X(0) = e^{-6}

P_X(1) = \frac{e^{-6}*6^1}{1!} = 6*e^{-6}

Hence,

P(X \geq 2) = 1-P(X < 2) = 1- 7*e^{-6} = 0.9826

c) For five minutes the mean is 15. We need to sum the probabilities of 0, 1 and 2.

P_X(0) = e^{-15}

P_X(1) = e^{15}*15

P_X(2) = \frac{e^{-15}*15^2}{2!} = 112.5*e^{-15}

As a result,

P(X \leq 2) = e^{-15}(1+15+112.5) = 0.000039308

Practically 0

4 0
2 years ago
Assuming that the Chinese population continues to grow at the same rate, how many years until the population reaches 1.5 billion
faltersainse [42]

Answer:

29 years

Step-by-step explanation:

The population of the Chinese people is 1.3 bn, and they grow at a rate of 0.49% per year. To get the number of years it requires to reach 1.5 bn, we use this method

after x years, the population will be

1.3 * 1.0049^x

so you just need to solve

1.3 * 1.0049^x = 1.5

1.0049^x = 1.5/1.3

x log 1.0049 = log(1.5/1.3)

x = log(1.5/1.3)/log(1.0049)

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2 years ago
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Answer:

449.10

Step-by-step explanation:

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