
the example on your picture uses A(n) and n = years, but is pretty much the same, in this case is t = years.
<span>A bond that closed today at 94 down 2 closed yesterday in dollars at </span>940 dollars
Answer: Esy the answer is; C.
Step-by-step explanation:
The higher the negative value the less or lower the number is.
CONFUSING Right? XD
When the demand and supply curve intersect, that is, where the quantity demanded and quantity supplied are equal, the market is said to be in equilibrium. Thus, the given quantity is equilibrium quantity.
From the graph, we see that when the production cost of wheat is $4, the equilibrium quantity is 600 units.
When the production cost lowers from $4 to $3, the supply of wheat increases, such that the equilibrium quantity increases from 600 units to 800 units.
Thus, after an increase in supply, the equilibrium quantity increases.
So, Option A is the correct answer.
<span>The number of dollars collected can be modelled by both a linear model and an exponential model.
To calculate the number of dollars to be calculated on the 6th day based on a linear model, we recall that the formula for the equation of a line is given by (y - y1) / (x - x1) = (y2 - y1) / (x2 - x1), where (x1, y1) = (1, 2) and (x2, y2) = (3, 8)
The equation of the line representing the model = (y - 2) / (x - 1) = (8 - 2) / (3 - 1) = 6 / 2 = 3
y - 2 = 3(x - 1) = 3x - 3
y = 3x - 3 + 2 = 3x - 1
Therefore, the amount of dollars to be collected on the 6th day based on the linear model is given by y = 3(6) - 1 = 18 - 1 = $17
To calculate the number of dollars to be calculated on the 6th day based on an exponential model, we recall that the formula for exponential growth is given by y = ar^(x-1), where y is the number of dollars collected and x represent each collection day and a is the amount collected on the first day = $2.
8 = 2r^(3 - 1) = 2r^2
r^2 = 8/2 = 4
r = sqrt(4) = 2
Therefore, the amount of dollars to be collected on the 6th day based on the exponential model is given by y = 2(2)^(5 - 1) = 2(2)^4 = 2(16) = $32</span>