Triangle KLM ~ triangle KQP are similar. Solve for x.
1 answer:
You might be interested in
Answer:
a) mt = -2
b) y=2-2x
Step-by-step explanation:
We have ⇒
and we must find
a) The slope of the tangent line to the curve at the point (1,0)
b) The equation of the tangent line in part (a)
a) with the point (1,0) then f'(x)
the slope (mt) in x=1 is
f'(1)= , m t= -2
b) mt=-2 at the point (1,0), knowing that the pending point model is:
, we solve y-0 = -2(x-1) ⇒ y=-2x+2
