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AURORKA [14]
1 year ago
7

Fiona can assemble a bookcase in 0.8 hour. She works for

Mathematics
2 answers:
AfilCa [17]1 year ago
5 0

Answer:

5

Step-by-step explanation:

0.8 hour = 0.8*60= 48

4 hours = 240

240/48= 5

Nataly_w [17]1 year ago
3 0

Answer:

Fiona can assemble 4 bookcases in 4 hours

equation: 0.8 times 5 = 4

Step-by-step explanation:

Hope this helps

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La fuerza necesaria para evitar que un auto derrape en una curva varía inversamente al radio de la curva y conjuntamente con el
Vika [28.1K]

Answer:

768 libras de fuerza

Step-by-step explanation:

Tenemos que encontrar la ecuación que los relacione.

F = Fuerza necesaria para evitar que el automóvil patine

r = radio de la curva

w = peso del coche

s = velocidad de los coches

En la pregunta se nos dice:

La fuerza requerida para evitar que un automóvil patine alrededor de una curva varía inversamente con el radio de la curva.

F ∝ 1 / r

Y luego con el peso del auto

F ∝ w

Y el cuadrado de la velocidad del coche

F ∝ s²

Combinando las tres variaciones juntas,

F ∝ 1 / r ∝ w ∝ s²

k = constante de proporcionalidad, por tanto:

F = k × w × s² / r

F = kws² / r

Paso 1

Encuentra k

En la pregunta, se nos dice:

Suponga que 400 libras de fuerza evitan que un automóvil de 1600 libras patine alrededor de una curva con un radio de 800 si viaja a 50 mph.

F = 400 libras

w = 1600 libras

r = 800

s = 50 mph

Tenga en cuenta que desde el

F = kws² / r

400 = k × 1600 × 50² / 800

400 = k × 5000

k = 400/5000

k = 2/25

Paso 2

¿Cuánta fuerza evitaría que el mismo automóvil patinara en una curva con un radio de 600 si viaja a 60 mph?

F = ?? libras

w = ya que es el mismo carro = 1600 libras

r = 600

s = 60 mph

F = kws² / r

k = 2/25

F = 2/25 × 1600 × 60² / 600

F = 768 libras

Por lo tanto, la cantidad de fuerza que evitaría que el mismo automóvil patine en una curva con un radio de 600 si viaja a 60 mph es de 768 libras.

7 0
2 years ago
If five friends want to share 1.25 of a pizza evenly how much pizza would each person get
Amanda [17]

1.25 /5

12/5 = 2  with 2 left over

25/5 = 5

2 numbers

1.25 /5 = .25

Each person gets .25 of a pizza

4 0
2 years ago
Read 2 more answers
Select the correct answer from each drop-down menu. Polygon ABCD goes through a sequence of rigid transformations to form polygo
Viktor [21]

Answer:

The sequence of transformations involved is a reflection across the x axis, followed by a reflection across the y = x line

Step-by-step explanation:

The polygon ABCD is shown in the image attached. The coordinates of the polygon are A(-6, 6), B(-4, 6), C(-4, 4), D(-6, 2), while the polygon A'B'C'D' is at A'(-6, -6), B'(-6, -4), C'(-4, -4), D'(-2, -6)

A transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, translation, dilation and rotation.

If a point O(x, y) is reflected across the x axis, the new coordinate is O'(x, -y).

If a point O(x, y) is reflected across the y = x line, the new coordinate is O'(y, x)

Hence if polygon ABCD is reflected across the x axis, the new coordinates are A*(-6, -6), B*(-4, -6), C*(-4, -4), D*(-6, -2). If a reflection across the y = x line, the new coordinates are A'(-6, -6), B'(-6, -4), C'(-4, -4), D'(-2, -6)

8 0
1 year ago
Ariel snowboarded down a mountain that has a vertical height of 1,200 feet. She traveled a distance of 2,400 feet from the top o
KIM [24]
For this case what you should do is use the following trigonometric relationship
 senx = (1200) / (2400)
 senx = 0.5
 Clearing the angle we have
 x = ASIN (0.5)
 x = 30
 Answer:
 The angle of elevation from the base to the top of the mountain is 30 °
6 0
2 years ago
In quadrilateral RSTU, RS = 60 mm, ST = 60 mm, TU = 112 mm, and UR = 112 mm.
lesya692 [45]

Answer:

A. factor 4

Step-by-step explanation:

Just choose any side of the original one e.g 60mm and divide it by the lenght of the same side of the new one. In A. this gives you 60mm/15mm = 4. Then you can multiply the other lengths with that factor and if the result is equal to the sides of your original one you found the solution.

5 0
2 years ago
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