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fredd [130]
2 years ago
13

Esmerelda simplified a complex fraction. Her work is shown below. Negative 5 and one-fourth divided by three-halves = negative S

tartFraction 21 over 4 EndFraction divided by three-halves = (Negative StartFraction 21 over 4 EndFraction) (Three-halves) = Negative StartFraction 24 over 6 EndFraction = negative 4
Mathematics
1 answer:
Sliva [168]2 years ago
8 0

Given:

The complex fraction is

\dfrac{-5\dfrac{1}{4}}{\dfrac{3}{2}}

Esmerelda simplified a complex fraction and steps are given.

To find:

The mistake of Esmerelda.

Solution:

We have,

\dfrac{-5\dfrac{1}{4}}{\dfrac{3}{2}}

Convert the mixed fraction in improper fraction.

\dfrac{-5\dfrac{1}{4}}{\dfrac{3}{2}}=\dfrac{-\dfrac{5\times 4+1}{4}}{\dfrac{3}{2}}

\dfrac{-5\dfrac{1}{4}}{\dfrac{3}{2}}=\dfrac{-\dfrac{20+1}{4}}{\dfrac{3}{2}}

\dfrac{-5\dfrac{1}{4}}{\dfrac{3}{2}}=\dfrac{-\dfrac{21}{4}}{\dfrac{3}{2}}

Use the reciprocal of the divisor.

\dfrac{-5\dfrac{1}{4}}{\dfrac{3}{2}}=-\dfrac{21}{4}\times \dfrac{2}{3}

\dfrac{-5\dfrac{1}{4}}{\dfrac{3}{2}}=-\dfrac{21\times 2}{4\times 3}

\dfrac{-5\dfrac{1}{4}}{\dfrac{3}{2}}=-\dfrac{42}{12}

\dfrac{-5\dfrac{1}{4}}{\dfrac{3}{2}}=-\dfrac{7}{2}

Therefore, the correct value of given fraction is -\dfrac{7}{2}.

Three mistakes of Esmerelda are:

1. Esmerelda added the numerators.

2. Esmerelda added the denominators.

3. Esmerelda did not use the reciprocal of the divisor.

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Step-by-step explanation:

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In the adjoining figure , AB = 6 , BC = 8 , <img src="https://tex.z-dn.net/?f=%20%5Cangle" id="TexFormula1" title=" \angle" alt=
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Here we are given with a triangle with smaller triangles formed due to the altitude on AC. Given:

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We have to find the value for sin \theta

So, Let's start solving....

In ∆ADB and ∆ABC,

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So, ∆ADB ~ ∆ABC (By AA similarity)

The corresponding sides will be:

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We know the value of AB and to find AC, we can use Pythagoras theoram that is:

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Coming back to the relation,

\sf{ \dfrac{AD}{6}  =  \dfrac{6}{10} }

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In ∆ADB, we have to find sin \theta which is given by perpendicular/base:

\sf{\sin( \theta)  =  \dfrac{AD}{AB} }

Plugging the values of AD and AB,

\sf{\sin( \theta)  =  \dfrac{3.6}{6} }

Simplifying,

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And this is our final answer.....

Carry On Learning !

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