Alright, lets get started.
If Matthew wants to complete packages at an average rate of at least 39 packages per hour.
And they worked 4 hrs only due to picnic, yesterday, it means they have to make
packages.
But they made only 112 packages means they are short of
packages.
Suppose they are working today t hrs, and his department will complete 43 packages per hour today.
It means they are going to make 43 t packages today.
This 43 t packages includes those 44 too , which they are short of yesterday due to picnic.
So, average will be
(39 average given in question)
Cross multiplying

Adding 44 in both sides


Subtracting 39 t in both sides


Dividing 4 in both sides
t = 11 hrs
Hence they have to woth 11 hrs today : Answer
Hope it will help :)
Answer:
Equal df
Step-by-step explanation:
Given that a chi square test for goodness of fit is used to examine the distribution of individuals across three categories,
Hence degree of freedom = 3-1 =2
Similarly for a chi-square test for independence is used to examine the distribution of individuals in a 2×3 matrix of categories.
Here degree of freedom = (r-1)(c-1) where r = no of rows and c =no of columns
= (2-1)(3-1) = 2
Thus we find both have equal degrees of freedom.
Two figures are similar if one is the scaled version of the other.
This is always the case for circles, because their geometry is fixed, and you can't modify it in anyway, otherwise it wouldn't be a circle anymore.
To be more precise, you only need two steps to prove that every two circles are similar:
- Translate one of the two circles so that they have the same center
- Scale the inner circle (for example) unit it has the same radius of the outer one. You can obviously shrink the outer one as well
Now the two circles have the same center and the same radius, and thus they are the same. We just proved that any two circles can be reduced to be the same circle using only translations and scaling, which generate similar shapes.
Recapping, we have:
- Start with circle X and radius r
- Translate it so that it has the same center as circle Y. This new circle, say X', is similar to the first one, because you only translated it.
- Scale the radius of circle X' until it becomes
. This new circle, say X'', is similar to X' because you only scaled it
So, we passed from X to X' to X'', and they are all similar to each other, and in the end we have X''=Y, which ends the proof.