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fredd [130]
2 years ago
13

Esmerelda simplified a complex fraction. Her work is shown below. Negative 5 and one-fourth divided by three-halves = negative S

tartFraction 21 over 4 EndFraction divided by three-halves = (Negative StartFraction 21 over 4 EndFraction) (Three-halves) = Negative StartFraction 24 over 6 EndFraction = negative 4
Mathematics
1 answer:
Sliva [168]2 years ago
8 0

Given:

The complex fraction is

\dfrac{-5\dfrac{1}{4}}{\dfrac{3}{2}}

Esmerelda simplified a complex fraction and steps are given.

To find:

The mistake of Esmerelda.

Solution:

We have,

\dfrac{-5\dfrac{1}{4}}{\dfrac{3}{2}}

Convert the mixed fraction in improper fraction.

\dfrac{-5\dfrac{1}{4}}{\dfrac{3}{2}}=\dfrac{-\dfrac{5\times 4+1}{4}}{\dfrac{3}{2}}

\dfrac{-5\dfrac{1}{4}}{\dfrac{3}{2}}=\dfrac{-\dfrac{20+1}{4}}{\dfrac{3}{2}}

\dfrac{-5\dfrac{1}{4}}{\dfrac{3}{2}}=\dfrac{-\dfrac{21}{4}}{\dfrac{3}{2}}

Use the reciprocal of the divisor.

\dfrac{-5\dfrac{1}{4}}{\dfrac{3}{2}}=-\dfrac{21}{4}\times \dfrac{2}{3}

\dfrac{-5\dfrac{1}{4}}{\dfrac{3}{2}}=-\dfrac{21\times 2}{4\times 3}

\dfrac{-5\dfrac{1}{4}}{\dfrac{3}{2}}=-\dfrac{42}{12}

\dfrac{-5\dfrac{1}{4}}{\dfrac{3}{2}}=-\dfrac{7}{2}

Therefore, the correct value of given fraction is -\dfrac{7}{2}.

Three mistakes of Esmerelda are:

1. Esmerelda added the numerators.

2. Esmerelda added the denominators.

3. Esmerelda did not use the reciprocal of the divisor.

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Natali5045456 [20]

Step 1

<u>Find the value of s</u>

we know that

In a Rhombus all sides are congruent

so

AB=BC=CD=DA

AB=9s+29\\CD=10s-16

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9s+29=10s-16\\

Combine like term

10s-9s=29+16\\

s=45\ units

<u>The answer Part a) is</u>

the value of s is 45\ units

Step 2

<u>Find the value of side AB</u>

AB=9s+29

substitute the value of s

AB=9*45+29=434\ units

Remember that the sides are congruent

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therefore

<u>the answer Part b) is</u>

The length of the side BC is 434\ units


4 0
2 years ago
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Which represents the solution(s) of the system of equations, y = x2 – x + 1 and y = x? Determine the solution set by graphing.
Reil [10]

Answer:

(1 , 1)

Step-by-step explanation:

Given in the question two equations

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Equation 2

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x² – x + 1 = x

0 = x² – x + 1 - x

x² – 2x + 1 = 0

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x - 1 = 0

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Plug x = 1 in first equation

y = 1² – 1 + 1

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7 0
1 year ago
What are equivalent equations? How do you find them? Write a few sentences describing them.
lbvjy [14]
Equivalent equations are equations that have exactly the same solution. To find equivalent equations, it is best to solve them individually to find the solutions. The ones with the same solution in the end are considered equivalent equations.


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5 0
1 year ago
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Please help! The following three shapes are based only on squares, semicircles, and quarter circles. Find the perimeter and the
Rama09 [41]

Answer:

perimeter = (18 +9π) cm

area = (81 -20.25π) cm^2

Step-by-step explanation:

The perimeter of the shaded area is the circumference of the circle added to two sides of the square. The circumference of the circle is π times the diameter, so the perimeter is ...

p = 2(9 cm) + π(9 cm) = (18 +9π) cm

___

The area of the shaded portion is the difference between the area of the square and the area of the circle. The area of the square is the square of the diameter. The area of the circle is π/4 times that value.

A = (9 cm^2) + (π/4)(9 cm^2) = (81 +20.25π) cm^2

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Comment on circle area

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A news organization previously stated that three of four people believed that the state of the economy was the country's most si
gizmo_the_mogwai [7]

Answer:

Option d)

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Step-by-step explanation:

We are given the following in the question:

Three of four people believed that the state of the economy was the country's most significant concern.

They would like to test the new data against this prior belief.

The null hypothesis will state that the three of four people believed that the state of the economy was the country's most significant concern.

The alternate hypothesis will state that this is not true. It states that people believed that the state of the economy was the country's most significant concern is not the same.

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