Ask question

Ask question

All categories

2 years ago

5

Suppose the function F(c) represents the earnings of a volleyball team from selling c cupcakes. They are selling each cupcake fo

r $2 each.
Which variable represents the domain? Interpret what it is in context.

Do positive or negative (or both) values for the input make sense in the context? Describe an appropriate domain of this function. Specify the upper limit and the lower limit.

Is it possible for the team to earn $50.50?

Please! I need help!

2 answers:

r-ruslan [8.4K]2 years ago

8 0

Answer:

c (no. of cupcakes)

No, only positive values

Appropriate domain: while numbers

Lower limit: 0, upper limit: positive infinity

Not possible

Step-by-step explanation:

Domain is the set of inputs/independent variable

Which in this case is no. of cupcakes sold

The domain can take values which are whole numbers,

0, 1, 2,..... infinity

F(c) = 50.50

2c = 50.50

c = 25.25 (not possible)

navik [9.2K]2 years ago

5 0

Answer:

The variable c represents the domain as it is the independent variable.

The domain of the function F(c) is given by c ≥ 0.

So, only positive values for the input make sense.

The upper limit of the domain is +∞ and lower limit is 0.

It is not possible for the team to earn $50.50 as it will be only multiple of 2.

Step-by-step explanation:

If F(c) represents the earning of a volleyball team from selling c cupcakes and each cupcake costs $2 each, then the equation that models the situation is

F(c) = 2c ..... (1)

The variable c represents the domain as it is the independent variable. (Answer)

The domain of the function F(c) is given by c ≥ 0. (Answer)

So, only positive values for the input make sense. (Answer)

The upper limit of the domain is +∞ and the lower limit is 0. (Answer)

It is not possible for the team to earn $50.50 as it will be only multiple of 2. (Answer)

You might be interested in

The leaning tower of Pisa in Italy appears to be cylindrical in shape. It’s height is about 56 meters. If the volume of the towe

zaharov [31]

Answer:1+1×2=4

Step-by-step explanation:

1 +1 =2 ×2 =4

6 0

1 year ago

Find the dimensions of the box with volume 1728 cm3 that has minimal surface area. (Let x, y, and z be the dimensions of the box

Gala2k [10]

Answer:

The dimensions of the box are 12 cm , 12 cm , 12 cm

Step-by-step explanation:

Let x , y and z be the dimensions of box

Volume of box =xyz=1728

$z=\frac{1728}{xy}$

Surface area of box = $2xy+2yz+2xz=2xy+2y(\frac{1728}{xy})+2x(\frac{1728}{xy})$

Let $f(x,y)=2xy+2(\frac{1728}{x})+2(\frac{1728}{y})$

To get minimal surface area

$\frac{\partial f}{\partial x}=0$ and $\frac{\partial f}{\partial y}=0$

$\frac{\partial(2xy+2(\frac{1728}{x})+2(\frac{1728}{y}))}{\partial x}=0$

$2y-2(\frac{1728}{x^2})=0$

$y=\frac{1728}{x^2}$ ----1

$\frac{\partial(2xy+2(\frac{1728}{x})+2(\frac{1728}{y}))}{\partial y}=0$

$2x-2(\frac{1728}{y^2})=0\\x=\frac{1728}{y^2} \\y^2=\frac{1728}{x}$

Using 1

$(\frac{1728}{x^2} )^2=\frac{1728}{x}$

x=0 and $x^3=1728$

Side can never be 0

So, $x^3=1728$

x=12

$y=\frac{1728}{x^2} \\y=\frac{1728}{12^2}$

y=12

$z=\frac{1728}{xy}\\z=\frac{1728}{(12)(12)}$

z=12

The dimensions of the box are 12 cm , 12 cm , 12 cm

5 0

2 years ago

Liono4ka [1.6K]

Answer:

Part 1: The polygon ABCDE reflected across y-axis to get the polygon MNOPQ. So, the polygon ABCDE congruent to polygon MNOPQ.

Part 2: The vertices of polygon VWXYZ are V(1, 3), W(-1, 7), X(-7, 7), Y(-5, 3), and Z(-3, 1).

Step-by-step explanation:

Part 1:

The vertices of the polygon ABCDE are A(2, 8), B(4, 12), C(10, 12), D(8, 8), and E(6, 6).

The vertices of the polygon MNOPQ are M(-2, 8), N(-4, 12), O(-10, 12), P(-8, 8), and Q(-6, 6).

We need to find the transformation or sequence of transformations that can be performed on polygon ABCDE to show that it is congruent to polygon MNOPQ.

The relation between the vertices of ABCDE and MNOPQ are defined as

$(x,y)\rightarrow (-x,y)$

It means the polygon ABCDE reflected across y-axis to get the polygon MNOPQ. So, the polygon ABCDE congruent to polygon MNOPQ.

Part 2:

If polygon MNOPQ is translated 3 units right and 5 units down, then

$(x,y)\rightarrow (x+3,y-5)$

$M(-2,8)\rightarrow V(-2+3,8-5)=V(1,3)$

$N(-4,12)\rightarrow W(-4+3,12-5)=W(-1,7)$

$O(-10,12)\rightarrow X(-10+3,12-5)=X(-7,7)$

$P(-8,8)\rightarrow Y(-8+3,8-5)=Y(-5,3)$

$Q(-6,6)\rightarrow Z(-6+3,6-5)=Z(-3,1)$

Therefore the vertices of polygon VWXYZ are V(1, 3), W(-1, 7), X(-7, 7), Y(-5, 3), and Z(-3, 1).

6 0

2 years ago

Steven has 20 tickets to use at the carnival. Jared has 4 tickets to use at the carnival. How many times as much is the amount o

sesenic [268]

5 times the amount pretty sure

5 0

1 year ago

Kendra made a scaled copy of the following square. She used a scale factor less than 111. What could be the side length of the s

ololo11 [35]

Answer:

2 units

1/4 unit

5 units

Step-by-step explanation:

Khan ^w^'

4 0

2 years ago