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tester [92]
2 years ago
7

You have a square flower garden that has an area of 400 square yards. What is the length of one side of the garden?

Mathematics
1 answer:
emmasim [6.3K]2 years ago
7 0

Answer:

20 yards

Step-by-step explanation:

The area of a square is calculated by multiplying its height by its base. Because they are the same in a square, the area of a square is obtained by squaring one of its sides. Let's call the sides 'x'. Then we can express the area of the garden as x^2=400.

From here we simply need to square root both sides which gives us:

x=20

Therefore the length of one side of the garden is 20 yards.

Hope this helped!

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Given BC = 2
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Answer:

a) P(5

And we can find this probability with this difference:

P(-1.90

And using the norma standard distribution or excel we got:

P(-1.90

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And using the complement rule we got:

P(Z>-1.096) =1-P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(7.37,1.25)  

Where \mu=7.37 and \sigma=1.25

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P(5

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(5

And we can find this probability with this difference:

P(-1.90

And using the norma standard distribution or excel we got:

P(-1.90

Part b

For this case we want this probability:

P(X>6)

And we can use the z score and we got:

P(X>6) =P(Z> \frac{6-7.37}{1.25}) = P(Z>-1.096)

And using the complement rule we got:

P(Z>-1.096) =1-P(Z

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2 years ago
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