Triangle xyz has sides xy = 3", yz = 4", and xz = 5". if angle y is a right angle, and side yz is opposite angle x, what is the
tan of angle x?
2 answers:
Answer:
Step-by-step explanation:
Please find the attachment.
We have been given that triangle xyz has sides xy = 3", yz = 4", and xz = 5". The angle y is a right angle and side yz is opposite angle x. We are asked to find the .
We know that tangent represents relation between opposite and adjacent side of right triangle.
We can see that adjacent side of our given triangle is xy, so we will get:
Therefore, tan of angle x is .
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Complete Question: Check the file attached to this document to see the complete question
Answer:
P(X < 7) = 0.76
Step-by-step explanation:
Counting properly from the diagram attached to the question,
number of trials it took her to make less than 7 shots(i.e. 0 to 6 shots) = 38
The total number of trials she made = 50
Probability that it takes fewer than 7 shots to get her first successful shot, P(X < 7) = (number of trials it took to make less than 7 shots)/(Total number of trials)
P(X < 7) = 38/50
P(X < 7) = 0.76
Answer:
We want a polynomial of smallest degree with rational coefficients with zeros in ,
and -3. The last root gives us the factor (x+3). Hence, our polynomial is
where is a polynomial with rational coefficients and roots
and
. The root
gives us a factor
, but in order to obtain rational coefficients we must consider the factor
.
An analogue idea works with . For convenience write
. This gives the factor
. Hence,
Notice that . So, in order to satisfy the last condition we divide by 3 the whole polynomial, without altering its roots. Finally, the wanted polynomial is
Step-by-step explanation:
We must have present that any polynomial it's determined by its roots up to a constant factor. But here we have irrational ones, in order to eliminate the irrational coefficients that a factor of the type will introduce in the expression, we need to multiply by its conjugate
. Hence, we will obtain
that have rational coefficients. Finally, the last condition is given with the intention to fix the constant factor. Usually it is enough to evaluate in the point and obtain the necessary factor.