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anyanavicka [17]

2 years ago

14

Tickets were sold at four different gates of a high school football stadium. The graph below shows the percent of the total tick

ets sold at each gate during a recent game. If 90 tickets were sold at gate c, what was the total number of tickets sold?

1 answer:

MaRussiya [10]2 years ago

6 0

you have to add 90 +90 3 times then theres your answer :)

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More and more businesses and homeowners are installing solar panels on their roofs to draw energy from the sun's rays. According

4vir4ik [10]

Answer:

S(2001) = 19.23

S(2002) = 37.22

Step-by-step explanation:

Given that;

S(t) = 0.73t^2 + 15.8t +2.7

t = 0 corresponding 2000

t = 1 then, its mean year 2001

so

S(2001) = 0.73(1)^2 + 15.8(1) +2.7

= 0.73 + 15.8 + 2.7

S(2001) = 19.23

also

t = 2 then, it means 2002

so

S(2002) = 0.73(2)^2 + 15.8(2) +2.7

= 2.92 + 31.6 + 2.7

S(2002) = 37.22

5 0

2 years ago

A conductor is mapping a trip and records the distance the train travels over certain time intervals.

leonid [27]

In half an hour the trains travels 22.5 miles

6 0

1 year ago

there is 90 5th grade students going on a field trip. each student gives the teacher $9.25 to cover admission to the theater and

Allisa [31]

(9.25x90-315)/90
(832.5-315)/90
517.5/90
5.75

5 0

1 year ago

Choose the correct simplification of the expression d3 ⋅ d5.

snow_tiger [21]

$d^3*d^5=d^{3+5}=d^8$

5 0

1 year ago

part 3. Find the value of the trig function indicated, use Pythagorean theorem to find the third side if you need it.

Nat2105 [25]

Answer: $\bold{9)\ \sin \theta=\dfrac{1}{3}\qquad 10)\ \sin \theta = \dfrac{4}{5}\qquad 11)\ \cos \theta = \dfrac{\sqrt{11}}{6}\qquad 12)\ \tan \theta = \dfrac{17\sqrt2}{26}}$

<u>Step-by-step explanation:</u>

Pythagorean Theorem is: a² + b² = c² , <em>where "c" is the hypotenuse</em>

<em />

$9)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{4}{12}\quad \rightarrow \large\boxed{\dfrac{1}{3}}$

Note: 4² + (8√2)² = hypotenuse² → hypotenuse = 12

$10)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{16}{20}\quad \rightarrow \large\boxed{\dfrac{4}{5}}$

Note: 12² + opposite² = 20² → opposite = 16

$11)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{\sqrt{11}}{6}\quad =\large\boxed{\dfrac{\sqrt{11}}{6}}$

Note: adjacent² + 5² = 6² → adjacent = √11

$12)\ \tan \theta=\dfrac{\text{side opposite of}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{17}{13\sqrt2}\quad =\large\boxed{\dfrac{17\sqrt2}{26}}$

Note: adjacent² + 7² = (13√2)² → adjacent = 17

5 0

2 years ago