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1 year ago

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a system of equations has infinitely many solutions. if 2y – 4x = 6 is one of the equations, which could be the other equation?

y = 2x 6 y = 4x 6 –y = –2x – 3 –y = –4x 6

2 answers:

deff fn [24]1 year ago

4 0

<span>A system of equations has infinitely many solutions when the two lines representing the equations coincide. i.e. the two equations are the same or a multiple of each other.
2y - 4x = 6
2y = 4x + 6
2y = 2(2x + 3)
y = 2x + 3
-y = -(2x + 3)
-y = -2x - 3
Hence the other equation is -y = -2x - 3</span>

BabaBlast [244]1 year ago

3 0

Answer:–y = –2x – 3

it's C on edg

Step-by-step explanation:

2y - 4x = 6

2y = 4x + 6

2y = 2(2x + 3)

y = 2x + 3

-y = -(2x + 3)

-y = -2x - 3

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2 years ago

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Make y the subject of the formula x=a-2by squared

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Answer:

y = ± $\sqrt{\frac{a-x}{2b} }$

Step-by-step explanation:

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1 year ago

Match each pair of points to the equation of the line that is parallel to the line passing through the points.

Paraphin [41]

we know that

If two lines are parallel, then, their slopes are equal.

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we will proceed to calculate the slope in each case, to determine the solution of the problem

<u>Case A)</u> Point $B(5,2)\ C(7,-5)$

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Substitute the values in the formula

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so

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therefore

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$B(5,2)\ C(7,-5)$ ------> $y=-3.5x-15$

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Find the slope DE

Substitute the values in the formula

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$m=-0.5$

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The equation $y=-0.5x-3$ is parallel to the line passing through the points $D(11,6)\ E(5,9)$

therefore

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$D(11,6)\ E(5,9)$ ------> $y=-0.5x-3$

<u>Case C)</u> Point $F(-7,12)\ G(3,-8)$

Find the slope FG

Substitute the values in the formula

$m=\frac{-8-12}{3+7}$

$m=\frac{-20}{10}$

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Any linear equation with slope $m=-2$ will be parallel to the line passing through the points $F(-7,12)\ G(3,-8)$

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Find the slope HI

Substitute the values in the formula

$m=\frac{9-4}{8-4}$

$m=\frac{5}{4}$

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so

The equation $y=1.25x+4$ is parallel to the line passing through the points $H(4,4)\ I(8,9)$

therefore

<u>the answer Part D) is</u>

$H(4,4)\ I(8,9)$ ------> $y=1.25x+4$

<u>Case E)</u> Point $J(7,2)\ K(-9,8)$

Find the slope JK

Substitute the values in the formula

$m=\frac{8-2}{-9-7}$

$m=\frac{6}{-16}$

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Any linear equation with slope $m=-0.375$ will be parallel to the line passing through the points $J(7,2)\ K(-9,8)$

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Find the slope LM

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dimaraw [331]

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Now we have to identify the like terms and simplify.

Like terms are nothing but the terms which have the same variables with same powers.

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Now combine the like terms

= 7mn^5 - 6m^6 +14m^2 n^4-5m^3n^3 + n^6

It can be written in standard form

= n^6 - 6m^6 + 7mn^5 + 14m^2n^4 -5m^3 n^3

The answer is D)

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