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scZoUnD [109]
2 years ago
5

The college has 700 students, and has issued student 388 parking permits. What is the percentage of students with parking permit

s?
Mathematics
1 answer:
andreyandreev [35.5K]2 years ago
4 0

55.4% ( to 1 decimal place )

to find percentage, make a fraction with parking permits issued on numerator and total students on denominator then multiply by 100%

percent of students with parking permits = \frac{388}{700} × 100% = 55.4%


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Jinghua hiked 4 1/2 miles through the woods in 2 1/4 hours. She hiked the return trip at the same average rate but by a differen
Anna007 [38]

Answer:

5 miles.

Step-by-step explanation:

Consider the question: Jinghua hiked 4 1/2 miles through the woods in 2 1/4 hours. She hiked the return trip at the same average rate but by a different route taking 2 1/2 hours. How many miles did Jinghua hike on the return trip ?

First of all, we will find Jinghua's speed using given information as:

\text{Speed}=\frac{\text{Distance}}{\text{Time}}

Convert mixed fractions into improper fractions:

4\frac{1}{2}\Rightarrow \frac{9}{2}

2\frac{1}{4}\Rightarrow \frac{9}{4}

\text{Jinghua's speed}=\frac{\frac{9}{2}\text{ Miles}}{\frac{9}{4}\text{ Hours}}

Using property \frac{\frac{a}{b}}{\frac{c}{d}}=\frac{ad}{bc}:

\text{Jinghua's speed}=\frac{9*4\text{ Miles}}{9*2\text{ Hours}}

\text{Jinghua's speed}=\frac{2\text{ Miles}}{\text{ Hour}}

We know that distance is equal to the product of speed and time.

\text{Distance}=\text{Speed}\times\text{Time}

Since we have been given that Jingua hiked the return trip at the same average rate, so distance covered by her on return trip would be speed (2 miles her hour) times given time (2 1/2 hours).

\text{Distance covered by Jingua on return trip}=\frac{2\text{ Miles}}{\text{ Hour}}\times 2\frac{1}{2}\text{ Hours}

\text{Distance covered by Jingua on return trip}=2\text{ Miles}\times \frac{5}{2}

\text{Distance covered by Jingua on return trip}=5\text{ Miles}

Therefore, Jingua hiked 5 miles on her return trip.

8 0
2 years ago
The student council raised $2,790 during its annual fundraiser. The money was shared equally among the Events Committee, the Spo
irina [24]

Answer:

77

Step-by-step explanation:

$2790 is shares equally between 3 committees. each committee would get - $2790 / 3 = $930

If a shirt costs $12 and the Sports Committee gets $930, the committee would get $930 / $12 = 77.5

The committee cannot get half a shirt, so the greatest number of shirt that can be purchased is 77

6 0
2 years ago
each volleyball team in a league needs 6 players 2 alternates, and a coach. How many teams can be formed with 288 peolple? show
mariarad [96]
You divide 288 by 6 and get the answer of 48
3 0
2 years ago
Read 2 more answers
This isosceles triangle has two sides of equal length, a, that are longer than the length of the base, b. The perimeter of the t
LuckyWell [14K]
Isosollese triangle has 2 equal sides that are longer than legnth of base
perimiter=15.7
equation is 2a+b=15.7
so if the longer side is 6.3, wat is legnth of base
we know that identical sides are bigger so 6.3 is one of the identical sides
2a means the 2 idneical sides
2(6.3)+b=15.7
12.6+b=15.7
subtract 12.6 from btohs ides
b=3.1
answer is base=3.1 cm
8 0
2 years ago
Read 2 more answers
Bobby's investment of $225,000 loses value at a rate of 3% per year. Use an exponential function to find the value of the invest
AleksAgata [21]

We have been given that Bobby's investment of $225,000 loses value at a rate of 3% per year. We are asked to find the value of the investment after 10 years.

We will us exponential decay function to solve our given problem.

We know that an exponential function is in form y=a\cdot (1-r)^x, where,

y = Final amount,

a = Initial amount,

r = Decay rate in decimal form,

x = Time.

Let us convert 3% into decimal.

3\%=\frac{3}{100}=0.03

Upon substituting a=\$225,000, r=0.03 and x=10, we will get:

y=\$225,000(1-0.03)^{10}

y=\$225,000(0.97)^{10}

y=\$225,000(0.7374241268949283)

y=\$165,920.4285513588675

Upon rounding to nearest dollar, we will get;

y\approx \$165,920

Therefore, the value of the investment after 10 years would be \$165,920.

5 0
2 years ago
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