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BabaBlast [244]
2 years ago
9

Three roots of the polynomial equation x4 - 4x3 - 2x2 + 12x + 9 = 0 are 3, -1 and -1. Explain why the fourth root must be a real

number. Find the fourth root.
Mathematics
1 answer:
LiRa [457]2 years ago
3 0
Descares Theorem says that the number of roots of a polynomial is equal to its highest exponent, and the roots could be real and/or imaginary (complex).

However is their is one complex root (a + i.b), it's conjugate is also
a root (a-i.b).

In the equation x⁴ - 4x³ - 2x² + 12x + 9 = 0, we have already 3 roots, then the 4rth cannot be a complex one since we don't have a fifth for its conjugate.

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Answer:

6x + 4y ≤ 50

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Step-by-step explanation:

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zysi [14]

Answer:

sin(30\°)*sin(60\°)=cos(60\°)*cos(30\°)

Step-by-step explanation:

we know that

sin(\alpha)=cos(\beta)

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so

sin(30\°)=cos(60\°)

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Because

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therefore

sin(30\°)*sin(60\°)=cos(60\°)*cos(30\°)

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ELEN [110]

Answer:

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3 0
2 years ago
Factorise 15x+ 18y???
anyanavicka [17]
Oh dear~This can only be simplified。
15X+18y
3(5X+6Y)
That's your answer.
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