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Oksi-84 [34.3K]

2 years ago

11

a trip to portland oregon, from boston will take 7 3/4 hours. Assuming we are two--thirds fo the way there, how much longer, in

hours, will the trip take?

1 answer:

aalyn [17]2 years ago

8 0

There is 2 7/12 hours left

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Each of 16 students measured the circumference of a tennis ball by four different methods, which were:Method A: Estimate the cir

lys-0071 [83]

Answer:

a) $\bar X_A =22.744$

$\bar X_B =20.7$

$\bar X_C =21.013$

$\bar X_D =18.306$

b) $Median_A =\frac{23+24}{2}=23.5$

$Median_B =\frac{20.4+20.4}{2}=20.4$

$Median_C =\frac{21+21}{2}=21$

$Median_D =\frac{20.7+20.7}{2}=20.7$

c) $\bar X_A =23.25$

$\bar X_B =20.7$

$\bar X_C =21.04$

$\bar X_D =20.69$

Step-by-step explanation:

Data given

Assuming the following data:

Method A: 18.0, 18.0, 18.0, 20.0, 22.0, 22.0, 22.5, 23.0, 24.0,24.0,25.0,25.0, 25.0,25.0,26.0,26.4

Method B: 18.8, 18.9, 18.9, 19.6, 20.1, 20.4, 20.4, 20.4, 20.4,20.5, 21.2. 22.0,22.0, 22.0,22.0,23.6

Method C: 20.2, 20.5, 20.5, 20.7, 20.8, 20.9, 21.0, 21.0,21.0,21.0, 21.0, 21.5,21.5,21.5,21.5,21.6

Method D: 20.0, 20.0, 20.0,-20.0, 20.2, 20.5, 20.5, 20.7, 20.7,20.7, 21.0, 21.1, 21.5, 21.6, 22.1,22.3.

Part a

The sample mean is defined as:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

If we apply this formula for the four methods we got:

$\bar X_A =22.744$

$\bar X_B =20.7$

$\bar X_C =21.013$

$\bar X_D =18.306$

Part b

Since the total number of points for each method is 16 and this is an even number we need to calculate the median as the average between the 8th and the 9th position of the data ordered from the smallest to the largest. If we do this we have that:

$Median_A =\frac{23+24}{2}=23.5$

$Median_B =\frac{20.4+20.4}{2}=20.4$

$Median_C =\frac{21+21}{2}=21$

$Median_D =\frac{20.7+20.7}{2}=20.7$

Part c

The trimmed mean by 20% means that we need to calculate removing the 20% from each of the tails, the 20% of 16 is 3.2, so we need to remove 3 observations from both ends of the data like this:

Method A: 20.0, 22.0, 22.0, 22.5, 23.0, 24.0,24.0,25.0,25.0, 25.0

Method B: 19.6, 20.1, 20.4, 20.4, 20.4, 20.4,20.5, 21.2. 22.0,22.0

Method C: 20.7, 20.8, 20.9, 21.0, 21.0,21.0,21.0, 21.0, 21.5,21.5

Method D: 20.0 20.2, 20.5, 20.5, 20.7, 20.7,20.7, 21.0, 21.1, 21.5.

If we calculate the mean for each method we got:

$\bar X_A =23.25$

$\bar X_B =20.7$

$\bar X_C =21.04$

$\bar X_D =20.69$

3 0

1 year ago

The edges of three squares are joined together to form a right triangle with legs of lengths R & S and a hypotenuse of lengt

dezoksy [38]

Answer:

$R^{2} + S^{2} = T^{2}$

Step-by-step explanation:

the pythagorean theorem

8 0

2 years ago

To increase an amount by 7% what single multiplier would you use?

vazorg [7]

You would multiply by 1.7

8 0

2 years ago

Read 2 more answers

The finances of a group of pet owners were analyzed to determine how much they were spending on their pet(s) each year. A graph

kvv77 [185]

Answer:

Option D.

Step-by-step explanation:

In the given graph x-axis represents the number of owners and y-axis represents yearly cost of pets, in hundreds.

It is given that the graph passes through the points (1,15), (3,7) and (10,0).

We need to check whether (4.5, 6) is a realistic solution for the function or not. (4.5,6) point represents

Number of owners = 4.5

yearly cost of pets = 6

It is realistic that owners spend $600 a year on their pet(s).

Number of owners can not be a fraction value. So, it is not realistic to have 4.5 owners.

Therefore, the correct option is D.

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2 years ago

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An astronaut on the moon throws a baseball upward. the astronaut is 6 ft, 6 in. tall, and the initial velocity of the ball is

marta [7]

Answer:

Step-by-step explanation:

The position function is

$s(t)=-2.7t^2+50t+6.5$ and if we are looking for the time(s) that the ball is 10 feet above the surface of the moon, we sub in a 10 for s(t) and solve for t:

$10=-2.7t^2+50t+6.5$ and

$0=-2.7t^2+50t-3.5$ and factor that however you are currently factoring quadratics in class to get

t = .07 sec and t = 18.45 sec

There are 2 times that the ball passes 10 feet above the surface of the moon, once going up (.07 sec) and then again coming down (18.45 sec).

For part B, we are looking for the time that the ball lands on the surface of the moon. Set the height equal to 0 because the height of something ON the ground is 0:

$0=-2.7t^2+50t+6.5$ and factor that to get

t = -.129 sec and t = 18.65 sec

Since time can NEVER be negative, we know that it takes 18.65 seconds after launch for the ball to land on the surface of the moon.

4 0

1 year ago