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stira [4]
1 year ago
11

Suppose the time to process a loan application follows a uniform distribution over the range of 8 to 13 days. What is the probab

ility that a randomly selected loan application takes longer than 12 days to process?
Mathematics
1 answer:
Arlecino [84]1 year ago
8 0

Answer: 0.2

Step-by-step explanation:

We know that , the probability density function for uniform distribution is given buy :-

f(x)=\dfrac{1}{b-a}, where x is uniformly distributed in interval [a,b].

Given : The time to process a loan application follows a uniform distribution over the range of 8 to 13 days.

Let x denotes the time to process a loan application.

So the probability distribution function of x for interval[8,13] will be :-

f(x)=\dfrac{1}{13-8}=\dfrac{1}{5}

Now , the probability that a randomly selected loan application takes longer than 12 days to process will be :-

\int^{13}_{12}\ f(x)\ dx\\\\=\int^{13}_{12}\dfrac{1}{5}\ dx\\\\=\dfrac{1}{5}[x]^{13}_{12}\\\\=\dfrac{1}{5}(13-12)=\dfrac{1}{5}=0.2

Hence, the probability that a randomly selected loan application takes longer than 12 days to process = 0.2

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The cubit is an ancient unit. Its length equals six palms. (A palm varies from 2.5 to 3.5 inches depending on the individual.) W
olasank [31]

Assuminhg the ark has a shoe-box (cuboid) shape it´s volume would be:

V_{cuboid}=lenght*width*height

We have this three measurements (l=300cubits;w=50cubits;h=30cubits)) and it can be as simple as replacing them in the equation and solving but they are in all in cubits. We will convert them to ft because the problem requires the answer in ft^{3}. In order to do this we will use the given equivalences:

1cubit=6palms\\1palm=3.10in

and another one:

1ft=12in

First we will convert from cubits to palms:

l=300cubits*\frac{6palms}{1cubit}=1800palms\\w=50cubits*\frac{6palms}{1cubit}=300palms\\h=30cubits*\frac{6palms}{1cubit}=180palms\\

now from palms to in:

l=1800palms*\frac{3.10in}{1palm}=5580in\\w=300palms*\frac{3.10in}{1palm}=930in\\h=180palms*\frac{3.10in}{1palm}=558in\\

now from in to ft:

l=5580in*\frac{1ft}{12in}=465ft\\w=930in*\frac{1ft}{12in}=77.5ft\\h=558in*\frac{1ft}{12in}=46.5ft

We can calculate the Volume now like this:

V_{ark}=465ft*77.5ft*46.5ft=1675743.75ft^{3}

The volume of trhe ark would be 1675743.75ft^{3}

6 0
1 year ago
Emma's sister is nine years older than Emma. Their combined ages add up to 49.How old is Emma. write and equation and solve
Genrish500 [490]
E= Emma's age
emma's sister's age= e+9 (emma's age plus 9)

e+9=49
(isolate your variable) 
e+9-9=49-9
e=40
Emma is 40 years old
To check: Emma's sister is 9 years older right? take emmas age 40 plus the nine more years and you still get the total of 49! hope that helps good luck
5 0
2 years ago
Read 2 more answers
When plucked, the high E string on a guitar has a frequency of 330 cycles per second. What sine function represents this note wh
Ber [7]

Let's analyse the function

y = f(x) = A\sin(\omega x)

The amplitude is A, so we want A=1.5

Now, we start at x=0, and we have 1.5\sin(0)=0

After one second, i.e. x=1, we want this sine function to make 330 cycles, i.e. the argument must be 330\cdot 2\pi

So, we have

f(1)=1.5\sin(\omega) = 1.5\sin(660\pi)

so, the function is

f(x) = 1.5\sin(660\pi x)

4 0
2 years ago
Read 2 more answers
A group of adults and students went on a class trip to Washington, DC. The number of male students was 1 more than 7 times the n
AVprozaik [17]
X number of male students
Y number of female students
Z number of the adults
X=(1 + 7)Z=8Z
Y= X/2
X +Y +Z = 82
8Z +8Z/2 +Z=82 implies Z=82/26=3.1
so we take Z= 3

X= 24
and Y = 12







5 0
2 years ago
A hole is drilled in a sheet-metal component, and then a shaft is inserted through the hole. The shaft clearance is equal to dif
VashaNatasha [74]

Answer:

(A)

P(X \geq 0.8) = \int\limits_{0.8}^{\infty} f(x) \, dx  = \int\limits_{0.8}^{1} 1.25(1-x^4) \, dx = 0.08192

(B)

Then the cumulative function would be

CF(x) = 1.25x - 0.25x^5       if   0<x<1

0 otherwise.

Step-by-step explanation:

(A)

We are looking for the probability that the random variable X is greater than 0.8.

P(X \geq 0.8) = \int\limits_{0.8}^{\infty} f(x) \, dx  = \int\limits_{0.8}^{1} 1.25(1-x^4) \, dx = 0.08192

(B)

For any  x you are looking for the probability P(X \geq x)  which is

P(X \geq x)  = \int\limits_{-\infty}^{x}  1.25(1-t^4) dt = \int\limits_{0}^{x}  1.25(1-t^4) dt = 1.25x - 0.25x^2

Then the cumulative function would be

CF(x) = 1.25x - 0.25x^5       if   0<x<1

0 otherwise.

5 0
2 years ago
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