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dusya [7]
2 years ago
10

Please help solve this using L.C.M and explain the steps plz ty.

Mathematics
1 answer:
Reptile [31]2 years ago
6 0

9514 1404 393

Answer:

  (x, y) = (2, 3)

Step-by-step explanation:

The first step is to find the least common multiple of the denominators of each of the equations. If the denominators have no common factors, a reasonable choice is their product. Here, it works to start with the fractions that must be added, then compare the LCM found to the denominator on the right to see if any further factors must be included.

<u>First equation</u>:

  LCM = 3×4 = 12

  12(2x/3 -y/4) = 12(7/12) . . . . . multiply the equation by 12

 8x -3y = 7 . . . . . . . . . simplify

<u>Second equation</u>:

  LCM = 4×5 =20

  20(3x/4 -2y/5) = 20(3/10) . . . . multiply equation by 20

  15x -8y = 6 . . . . . . simplify

<u>Solve by elimination</u>

We can eliminate the y-variable by subtracting 3 times the second equation from 8 times the first:

  8(8x -3y) -3(15x -8y) = 8(7) -3(6)

  19x = 38 . . . . . simplify

  x = 2 . . . . . . . divide by 19

Substituting into the first equation gives ...

  8(2) -3y = 7

  3y = 9 . . . . . . add 3y-7

  y = 3 . . . . . divide by 3

The solution is ...

  (x, y) = (2, 3)

_____

There are many ways to solve such a system of equations. Using the LCM to eliminate fractions is one way to start. You can also do the arithmetic with the fractions intact, though most folks don't care to. In addition to the elimination method used here, you can use matrix or graphical methods, substitution, or any of the variations of Cramer's Rule.

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Answer:

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3 0
2 years ago
HAVING BAD DAY HELP
ElenaW [278]
12s, you don’t have a value for s, so the problem can’t be fully solved but if you did you would multiply 12 by her speed

Hope this helps
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2 years ago
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The number of hours a group of contestants spends preparing for a quiz show is listed below. What is the frequency table that re
harkovskaia [24]
I'll just show you how to make a frequency table using the above data. 
We will group the data into class intervals and determine the frequency of the group.

<span>8 12 25 32 45 50 62 73 80 99 4 18 9 39 36 67 33
</span>
smallest data value = 4
highest data value = 99
difference = 99 - 4 = 95
number of data = 17

Let us assign a class interval of 20.

Class Interval     Tally                              Frequency
0-20                    8, 12, 4, 18, 9,                     5
21-40                25, 32, 39, 36, 33                 5 
41-60                45, 50, 67                              3
61-80                62, 73, 80                              3
81-100              99                                           1

That is how a frequency table look like. Usually, under the Tally column, tick marks are written instead of the numbers but for easier monitoring, I used the numbers in the data set.
8 0
2 years ago
At present the sum of Monica's age and daughter's age is 44 years. . After 2 years Monica's age will be three times that if her
sergeinik [125]

Answer:

Monica's age = 34 years

Her daughter's age = 10 years

Step-by-step explanation:

Let Monica's age = x

Let her daughter'sage = y

x + y = 44   -------> equ 1

After 2 years:

Monica's age = x + 2

Her daughter's age = y + 2

x + 2 = 3 * (y+2)

x + 2 = 3y + 6

      x = 3y + 6 -2

      x = 3y + 4

Put x value in equ 1:

    3y + 4 + y = 44

            4y = 44 - 4

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               y = 40/4

               y = 10

x = 44 -10

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7 0
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Umm 8/12 or 2/3 .......................................................................
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