Question

What is the difference of the polynomials?(–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5)A–6x4y – 2x3y2 + 9x2y3 – 3xy4 + y5B–6x4y – 2x3y2 – x2y3 – 3xy4 – y5C–6x4y + 3x3y2 + 4x2y3 – 3xy4 + y5D–6x4y – 7x3y2 + 4x2y3 – 3xy4 – y5

Answer 1

We have to calculate the difference of the given polynomials, we follows as:

$(-2x^{3}y^{2}+4x^{2}y^{3}-3xy^{4})-(6x^{4}y-5x^{2}y^{3}-y^{5})$

After opening the brackets, the signs of all the terms changes as there is negative sign before the bracket.

=$(-2x^{3}y^{2}+4x^{2}y^{3}-3xy^{4})-6x^{4}y+5x^{2}y^{3}+y^{5})$

Combining all the like terms, we get as

=$(-2x^{3}y^{2})+(4x^{2}y^{3}+5x^{2}y^{3})-3xy^{4}-6x^{4}y+y^{5}$

=$-2x^{3}y^{2}+9x^{2}y^{3}-3xy^{4}-6x^{4}y+y^{5}$

Option A is the correct answer.

Answer 2

Answer:

A A A A A A A A A A

Step-by-step explanation:

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