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horrorfan [7]
2 years ago
12

Mark adopt a dog today and it’s at the pet store looking for dog food he reMark adopt a dog today at the pet store looking for d

og food he researched The different brands before coming to the store and now he just needs to decide between two brands. Doggie delights cost $46 for a 20 pound bag. Natures choice cost $55 for a 25 pound bag. Mark wants to compare the cost of dog food per pound to find a better deal. Which bag Shumark byThe different brands before coming to the store and now he just needs to decide between two brands. Doggie delights cost $46 for a 20 pound bag. Natures choice cost $55 for a 25 pound bag. Mark wants to compare the cost of dog food prepared to find a better deal. Which bag should mark but ???
Mathematics
1 answer:
yarga [219]2 years ago
7 0
To get the answer you have to figure out the cost per pound for both bags. Do this by setting up fractions then reducing. 46$/20lbs is 2.3$ per pound, and 55$/25lbs is 2.2$ per pound making natures choice the better choice
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THIS IS URGENT I NEED THIS AS SOON AS POSSIBLE! YOUR HELP WOULD BE GREATLY APPRECIATED!
serious [3.7K]

Answer:

Strawberries sold 44 baskets

Raspberries sold 52 baskets

Step-by-step explanation:

4x + 9y = 644 \\ x + y = 96 \\ 4x + 4y = 384  \\ 5y = 260 \\ y = 52 \\ x = 44

7 0
2 years ago
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The blue M&M was introduced in 1995. Before then, the color mix in a bag of plain M&Ms was (30% Brown, 20% Yellow, 20% R
IRISSAK [1]

Answer:

The probability that the yellow M&M came from the 1994 bag is 0.07407 or 7.407%

Step-by-step explanation:

Given

Before 1995

(Br) Brown = 30%

(Y) Yellow = 20%  =0.2

(R) Red = 20%

(G) Green =10%  =0.1

(O) Orange = 10%

(T) Tan = 10%

 

After 1995

(Br) Brown = 13%

(Y) Yellow = 14%  =0.14

(R) Red = 13%

(G) Green = 20% = 0.2

(O) Orange = 16%

(Bl) Blue = 24%

Since there are two bags, let A be the bag from 1994, and B be the bag from 1996

Then let AY imply we drew a yellow M&M from the 1994 bag

AG implies we drew a green M&M from the 1994 bag

BY implies imply we drew a yellow M&M from the 1996 bag

BG implies we drew a green M&M from the 1996 bag

P(AY) =0.2

P (BY) = 0.14

P(AG) =0.1

P(BG) =0.2

Since the draws from the 1994 and 1996 bag are independent,

therefore

P(AY n BG) = 0.2 * 0.2 = 0.04  -------(1)\\P(AG n BY) =0.1 * 0.14 =0.014   --------(2)\\

The draws can happen in either of the 2 ways in (1) and (2) above

therefore total probability E is given as

E =P( AY n BG) u P(AG n BY)\\=0.04 + 0.014 =0.O54

For the yellow one to be from 1994, it implies that the event to be chosen is

P(AYnBG) = 0.2*0.2

Since the total probability is given as E=0.054

then P((AYnBG) /E) =\frac{0.04}{0.054} = 0.07407

Concluding statement: This is the condition for the Yellow one to come from 1994 and green from 1996 provided that they obey the condition from E

4 0
2 years ago
the price of a pack of gum today is 63 cents. this is 3 cents more than three times the price ten years ago. what was the price
Paul [167]
The answer would be .43 
7 0
2 years ago
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The probability of flowering plants bearing flowers in January is given the table. If a plant has flowered in January, what is t
ololo11 [35]

Answer:

Probability of a flowering plant bearing flowers in January if it is a peony= 70 %

Step-by-step explanation:

We know that:

Probability =Total favourable outcomes/ Total possible outcomes

Probability of flowering plants bearing flowers in January is given in the table. It means that out of 100 peony  70 peony flowers in January.

There are five kinds of flowers.

We have to select peony and find it's Probability.

As all flowers are independent, their flowering phenomenon does not depend on each other.

So,Probability of a flowering plant bearing flowers in January if it is a peony= 70 %

7 0
1 year ago
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a child starts a piggy bank with $2. each day, the child receives 25 cents at the end of the day and puts it in the bank. if A r
Troyanec [42]

For a given function f(x), the domain is the set of possible values of x that we can use and the range is the set of the possible values of f(x).

For both points we will find that the answer is:

"We only can evaluate the function with integer values of d."

a) Here we have the function:

A(d) = 2 + 0.25*d

The first thing we want to answer is:

"explain why the domain does not contain the value d=2.5 "

We know that at the end of each day the kids get's the $0.25, so at d= 2.5 there two days and a half, and because only 2 nights passed, at this moment the kid only got the money two times.

So for d = 2.1

           d = 2.5

           d = 2.7

etc

We would get the exact same total money, thus we only can evaluate the function with integer values of d.

b) Why the range does not include the value A = $3.10?

Remember that d can only be an integer number.

Now let's solve:

A(d) = 3.10 = 2 + 0.25*d

          3.10 - 2 = 0.25*d

          1.10 = 0.25*d

           1.10/0.25 = d = 4.4

So we only can get  A = $3.10 if d = 4.4, and remember that d only can be a whole number, this is why the range does not include the value $3.10

If you want to learn more, you can read:

brainly.com/question/1632425

8 0
1 year ago
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