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umka21 [38]
2 years ago
12

The percentage of U.S. college freshmen claiming no religious affiliation has risen in recent decades. The bar graph shows the

Mathematics
1 answer:
emmainna [20.7K]2 years ago
3 0

Answer:

0.5%/year

24.2%

Step-by-step explanation:

Estimate the average yearly increase in the percentage of first-year college females claiming no religious affiliation

Percentage of females by year:

1980 = 6.2%

1990 = 10.8%

2000 = 13.6%

2012 = 21.7%

Average yearly increase :

Percentage increase between 1980 - 2012 :

2012% - 1980% = ( 21.7% - 6.2%) = 15.5% increase over [(2012 - 1980)] = 32 years

15.5 % / 32 years = 0.484375% / year = 0.5%/year

b. Estimate the percentage of first-year college females who will claim no religious affiliation in 2030,

Given an average increase of 0.484375% / year

(2030 - 1980) = 50 years

Hence by 2030 ; ( 50 years × 0.484375%/year) = 24.218% will claim no religious affiliation.

=24.2% (nearest tenth)

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Find the correlation coefficient of the line of best fit for the points (-3,-40), (1,12), (5,72), (7,137). Explain how you guy y
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Answer:

r = 0.9825; good correlation.

Step-by-step explanation:

One formula for the correlation coefficient is  

r = \dfrac{n\sum{xy} - \sum{x} \sum{y}}{\sqrt{n\left [\sum{x}^{2}-\left (\sum{x}\right )^{2}\right]\left [\sum{y}^{2}-\left (\sum{y}\right )^{2}\right]}}

The calculation is not difficult, but it is tedious.

1. Calculate the intermediate numbers

We can display them in a table.

      <u> </u><u>x</u>    <u>  y </u>   <u>  xy </u>  <u> x² </u>    <u>   y²   </u>

      -3   -40    120     9     1600

       1      12      12      1        144

       5    72   360   25      5184

     <u>  7</u>   <u>137</u>  <u> 959</u>   <u>49</u>    <u>18769 </u>

Σ = 10   181  1451   84   25697

2. Calculate the correlation coefficient

r = \dfrac{n\sum{xy} - \sum{x} \sum{y}}{\sqrt{\left [n\sum{x}^{2}-\left (\sum{x}\right )^{2}\right]\left [n\sum{y}^{2}-\left (\sum{y}\right )^{2}\right]}}\\\\= \dfrac{4\times 1451 - 10\times 181}{\sqrt{[4\times 84 - 10^{2}][4\times25697 - 181^{2}]}}\\\\= \dfrac{5804 - 1810}{\sqrt{[336 - 100][102788 - 32761]}}\\\\= \dfrac{3994}{\sqrt{236\times70027}}\\\\= \dfrac{3994}{\sqrt{16526372}}\\\\= \dfrac{3994}{4065}\\\\= \mathbf{0.9825}

The closer the value of r is to +1 or -1, the better the correlation is. The values of x and y are highly correlated.

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2 years ago
Find the value of $x$ that maximizes $$f(x) = \log (-20x + 12\sqrt{x}).$$ If there is no maximum value, write "NONE".
kakasveta [241]
The function is written as:
f(x) = log(-20x + 12√x)
To find the maximum value, differentiate the equation in terms of x, then equate it to zero. The solution is as follows.

The formula for differentiation would be:
d(log u)/dx = du/u ln(10)
Thus,
d/dx = (-20 + 6/√x)/(-20x + 12√x)(ln 10) = 0
-20 + 6/√x = 0
6/√x = 20
x = (6/20)² = 9/100

Thus,
f(x) =  log(-20(9/100)+ 12√(9/100)) = 0.2553

<em>The maximum value of the function is 0.2553.</em>
5 0
2 years ago
(1 Convert the integral below to polar coordinates and evaluate the integral. ∫4/2√0∫16−y2√yxydxdy∫04/2∫y16−y2xydxdy Instruction
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Answer:

A = 0

B = π/4

C = 0

D = 4

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Step-by-step explanation:

∫BA∫DC∫AB∫CD is shown in the picture attached

4 0
2 years ago
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Answer:

The area of the original piece of paper is 60cm

8 0
2 years ago
Read 2 more answers
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Answer: You invested $6000 in both accounts.

Step-by-step explanation:

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Let y represent the amount invested in the account earning 5% interest.

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R represents interest rate

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Considering the account earning 5%

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540 - 0.045y + 0.05y = 570

- 0.045y + 0.05y = 570 - 540

0.005y = 30

y = 30/0.005 = 6000

x = 12000 - y = 12000 - 6000

x = $6000

6 0
2 years ago
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