Step-by-step explanation:
dA/dt = 6 − 0.02A
dA/dt = -0.02 (A − 300)
Separate the variables.
dA / (A − 300) = -0.02 dt
Integrate.
ln(A − 300) = -0.02t + C
Solve for A.
A − 300 = Ce^(-0.02t)
A = 300 + Ce^(-0.02t)
Use initial condition to find C.
50 = 300 + Ce^(-0.02 × 10)
50 = 300 + Ce^(-0.2)
-250 = Ce^(-0.2)
C = -250e^(0.2)
A = 300 − 250e^(0.2) e^(-0.02t)
A = 300 − 250e^(0.2 − 0.02t)
Hey there!
Before you start solving anything, you need to identify which situation you want to call event A and which you want to call event B. I usually just do it in the order of the events as they're given to me in the question, so:
A = S<span>tudent participates in student council
B = S</span><span>tudent participates in after school sports
Any problems that contain the word "given" in the question portion will want you to refer to </span>P(A | B)<span> = P(</span>A ∩ B)/P(B). P(A | B) literally means "probability of event A, given that event B has occurred." P(A ∩ B) is the probability of event A and B happening, and P(B) is just the probability of event B happening. We've been given all of that, so:
P(A | B) = P(A ∩ B)/P(B)
P(A | B) = 11% / 62%
P(A | B) = 0.11 / 0.62
P(A | B) = 0.18
There will be about an 18% chance that <span>a student participates in student council, given that the student participates in after school sports.
Hope this helped you out! :-)</span>
Sinα=h/L where h=height, L=string length...
h=Lsinα so
h(25°)=50sin25≈21.1ft
h(45°)=50sin45≈35.4ft
<em><u>Your answer: </u></em> a reflection across the y-axis followed by a clockwise rotation 90° about the origin. A clockwise rotation 90° about the origin followed by a reflection across the x-axis. A counter-clockwise rotation 90° about the origin followed by a reflection across the y-axis. A reflection across the x-axis followed by a counter-clockwise rotation 90° about the origin.
Hope this helps <3
Stay safe
Stay Warm
-Carrie
Ps. It would mean a lot if you marked this brainliest
