Question

liquid product with 10% product solids is blended withsugar before being concentrated (removal of water) to obtaina final product with 15% product solids and 15% sugarsolids. Determine the quantity of final product obtainedfrom 200 kg of liquid product. How much sugar is required?Compute mass of water removed during con

Answer 1

Answer:

mass of the water removed =  66.67 kg

Step-by-step explanation:

given data

solids is blended with sugar = 10%

obtain  final product = 15% product

obtain  final product = 15% sugar solids

The initial product is = 200 kg

solution

we get here amount of sugar required that is

amount of sugar required = 200 × $\frac{10}{100}$

amount of sugar required =  20 kg

and we know total solid  = product solids +  sugar solids    ...............1

and

initial product =  final product    

so

0.20 ×  200kg= 0.30 ×  mass of the final product

mass of final product = 133.33 kg

but here

final product = 15% product solids and 15% sugar solids

so that amount of product solid = sugar solid

so

mass of the water removed = 200 kg - 133.33 kg

mass of the water removed =  66.67 kg